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Nadusha1986 [10]
3 years ago
6

How would you write x+3y=3 in y=mx+b format

Mathematics
2 answers:
Triss [41]3 years ago
8 0
X+3y=3
First add subtract the x
3y=-x+3
Then divide 3
Y=-1/3x+1
fomenos3 years ago
8 0
Your first step to putting x+3y=3 into slope-intercept form is to move x to the other side using subtraction.
 x+3y= 3
-x____-x
3y=-x+3

And the final step is to divide both sides by 3 so that you can isolate y and achieve slope-intercept form.
3y=-x+3
/3    /3
y=-1/3x+1

So, x+3y=3 in slope-intercept form would be y=-1/3x+1, where the slope (rise/run) is -1/3 and the line intersects the y-axis at point (0,1).
Remember, in y=mx+b, m represents slope and b represents the y-intercept of the equation's line when graphed.
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Can someone find the expression for h in terms of x.
PilotLPTM [1.2K]
The volume of the cylinder is equal to the sum of all spheres
the volume of 1 sphere is V1=4/3×pi×(1/2 x)³
simplified V1=1/6×pi×x² 
we conclude that the volume of the cylinder is V2=270V1
V2=45×pi×x³
also the V2 can be calculated from the cylinder 
V2= base(circle)×height
V2=(3x)²×pi×h=9x²×h
so we have 
9x²×pi×h=45×pi×x³
simplified h=5x
7 0
3 years ago
Maria bought seven boxes. A week later half of all her boxes were destroyed in a fire. There are now only 22 boxes left. With ho
Licemer1 [7]
Maria started with 37 boxes 
3 0
3 years ago
Okay how about this,
RideAnS [48]

Answer:

0.36

Step-by-step explanation:

4/11

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4 0
3 years ago
Write a real-world situation that could be modeled by the equation X + 12 = 50?
slavikrds [6]

Answer:

there were 50 apples at the store. 12 of them were green, how many of the 50 apples were red?

Step-by-step explanation:

7 0
2 years ago
Given: ABCD trapezoid, BK ⊥ AD , AB=DC AB=8, AK=4 Find: m∠A, m∠B
Elis [28]

Answer:

m\angle B=m\angle C=120^{\circ}

m\angle A=m\angle D=60^{\circ}

Step-by-step explanation:

Trapezoid ABCD is isosceles trapezoid, because AB = CD (given). In isosceles trapezoid, angles adjacent to the bases are congruent, then

  • \angle A\cong \angle D;
  • \angle B\cong \angle C.

Since BK ⊥ AD, the triangle ABK is right triangle. In this triangle,  AB = 8, AK = 4. Note that the hypotenuse AB is twice the leg AK:

AB=2AK.

If in the right triangle the hypotenuse is twice the leg, then the angle opposite to this leg is 30°, so,

m\angle ABK=30^{\circ}

Since BK ⊥ AD, then BK ⊥ BC and

m\angle KBC=90^{\circ}

Thus,

m\angle B=30^{\circ}+90^{\circ}=120^{\circ}\\ \\m\angle B=m\angle C=120^{\circ}

Now,

m\angle A=m\angle D=180^{\circ}-120^{\circ}=60^{\circ}

7 0
3 years ago
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