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Mashcka [7]
3 years ago
8

Can someone please help me I have a few more also that I need help with.

Mathematics
1 answer:
pychu [463]3 years ago
3 0

Answer:

77

Step-by-step explanation:

Please mark as brainliest. I'm happy to help

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Help needed!<br> What is the area of the figure below?<br><br> The figure is shown.
mixer [17]
My guess is 3,780 you have to multiply
8 0
4 years ago
Read 2 more answers
Simplify y-2/3/y+1/5
liberstina [14]

Answer:

\frac{15y-10}{15y-3}

Step-by-step explanation:

First at all, we need to use a=\frac{a}{1} to convert this expression into a fraction, like:

y-\frac{2}{3} to convert into \frac{y}{1} -\frac{2}{3}.

Expand the fraction to get the least common denominator, like

\frac{3y}{3*1}-\frac{2}{3}

Write all numerators above the common denominator, like this:

\frac{3y-2}{3}

The bottom one used the same way to became simplest form, like this:

y+\frac{1}{5}

\frac{y}{1} +\frac{1}{5}

\frac{5y}{5*1}+\frac{1}{5}

\frac{5y+1}{5}

And it became like this:

\frac{3y-2}{3}/\frac{5y+1}{5}

Now, we are going to simplify this complex fraction. We can use cross- multiply method to simplify this fraction.

\frac{3y-2}{3}*\frac{5y+1}{5}

3y-2(5) and 5y-1(3)

and it will becomes like this in function form:

\frac{3y-2(5)}{5y+1(3)}

Then, we should distribute 5 through the parenthesis

\frac{15y-10}{5y+1(3)}

\frac{15y-10}{15y+3}

And.... Here we go. That is the answer.

7 0
3 years ago
if theres a 30% chance of sun tomorrow and a 40% chance of wind and no.sun, what is the probability that it is windy, given that
Inessa [10]
20% is the answer 

Hope that helped :)
3 0
3 years ago
From a window 20 feet above the ground, the angle of elevation to the top of a building across
Nikitich [7]

Answer: The answer is 381.85 feet.

Step-by-step explanation:  Given that a window is 20 feet above the ground. From there, the angle of elevation to the top of a building across  the street is 78°, and the angle of depression to the base of the same building is 15°. We are to calculate the height of the building across the street.

This situation is framed very nicely in the attached figure, where

BG = 20 feet, ∠AWB = 78°, ∠WAB = WBG = 15° and AH = height of the bulding across the street = ?

From the right-angled triangle WGB, we have

\dfrac{WG}{WB}=\tan 15^\circ\\\\\\\Rightarrow \dfrac{20}{b}=\tan 15^\circ\\\\\\\Rightarrow b=\dfrac{20}{\tan 15^\circ},

and from the right-angled triangle WAB, we have'

\dfrac{AB}{WB}=\tan 78^\circ\\\\\\\Rightarrow \dfrac{h}{b}=\tan 15^\circ\\\\\\\Rightarrow h=\tan 78^\circ\times\dfrac{20}{\tan 15^\circ}\\\\\\\Rightarrow h=361.85.

Therefore, AH = AB + BH = h + GB = 361.85+20 = 381.85 feet.

Thus, the height of the building across the street is 381.85 feet.

8 0
4 years ago
Emma had some apples in her basket. Then, she picked 9 more apples. She gave 14 apples to Klara. She had 10 apples left. How man
RoseWind [281]
(x+9)-14=10
Add 14 to each side
x+9 = 24
Subtract 9 from each side
x = 15
7 0
3 years ago
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