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3 years ago

John wants to send a letter to Peter, who lives on Tesla

Mathematics

1 answer:

blondinia [14]3 years ago

5 0

Answer:

The minimum number of letters John has to send to be sure that Peter receives his letter is 127 letters

Step-by-step explanation:

The four digit numbers that are multiples of 5 and 7 with the last digit = 0 is found as follows

Since the last digit of the house number = 10, then the house number is divisible by 10 which also meets the condition that the house number is divisible by 5

We have the four digit numbers from 1000 to 9999

Hence the numbers divisible by both 7 and 10 are from (1000/70 (Which is 14 + 2/7) - 2/7)×70 + 70 = 1050 to (9999/70 (Which is 142 + 59/70)- 59/70)×70= 9940

Which gives 142 - 15 = 127 numbers which are four digit number multiples of 5 and 7 with the last digit = 0

Hence the minimum number of letters John has to send to be sure that Peter receives his letter = 127 letters.

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rusak2 [61]

The price of each caramel macchiato is $5.60

What is the correct function in this case?

The appropriate function is the one that considers the initial amount of $35 , the amount spent for 5 caramel macchiatos, and the balance left which is $7 after the purchase

This means the $35 minus the amount spent equals $7

let us assume that the price per item is x for 5 items, then he spent 5x

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1 year ago

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Mariulka [41]

Answer:

a) True

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

Step-by-step explanation:

Step(i):-

Given that the definite integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha$

we know that the trigonometric formula

sin²∝+cos²∝ = 1

cos²∝ = 1-sin²∝

step(ii):-

Now the integration

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha = \int\limits^\pi _0 {(\sqrt{cos^{2} \alpha } } \, )d\alpha$

= $\int\limits^\pi _0 {cos\alpha } \, dx$

Now, Integrating

$= ( sin\alpha )_{0} ^{\pi }$

= sin π - sin 0

= 0-0

= 0

Final answer:-

$\int\limits^\pi _ {0} \,(\sqrt{1-sin^{2}\alpha } )d\alpha =0$

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2 years ago

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8_murik_8 [283]

1/12
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Hope this helped! :)

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2 years ago