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Shalnov [3]
3 years ago
8

John wants to send a letter to Peter, who lives on Tesla

Mathematics
1 answer:
blondinia [14]3 years ago
5 0

Answer:

The minimum number of letters John has to send to be sure that Peter receives his letter is 127 letters

Step-by-step explanation:

The four digit numbers that are multiples of 5 and 7 with the last digit = 0 is found as follows  

Since the last digit of the house number = 10, then the house number is divisible by 10 which also meets the condition that the house number is divisible by 5

We have the four digit numbers from 1000 to 9999

Hence the numbers divisible by both 7 and 10 are from (1000/70 (Which is 14 + 2/7) - 2/7)×70 + 70 = 1050 to (9999/70 (Which is 142 + 59/70)- 59/70)×70= 9940

Which gives 142 - 15 =  127 numbers which are four digit number multiples of 5 and 7 with the last digit = 0

Hence the minimum number of letters John has to send to be sure that Peter receives his letter = 127 letters.

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Answer:

solution below

Step-by-step explanation:

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6C1*(0.34)¹*(0.66)⁵

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= 0.2555

<u>3. When X = 2</u>

6C2*(0.34)²*(0.66)⁴

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= 0.3289

<u>4. When x = 3</u>

6C3*(0.34)³*(0.66)³

20 x 0.039304 x 0.2875

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<u>5. When X = 4</u>

6C4*(0.34)⁴*(0.66)²

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<u>6. When x = 5</u>

6C5*(0.34)⁵*(0.66)¹

= 6 x 0.0045 x 0.66

= 0.01782

<u>7. When x = 6</u>

6C6*(0.34)⁶*(0.66)⁰

1 x 0.0015 x 1

= 0.0015

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