Answer:
11/24 is left over
Step-by-step explanation:
1/6 + 3/8 = 13/24
24/24 - 13/24 = 11/24
11/24 of the budget is left over
Hope this helps
Answer:
The Taylor series of f(x) around the point a, can be written as:
![f(x) = f(a) + \frac{df}{dx}(a)*(x -a) + (1/2!)\frac{d^2f}{dx^2}(a)*(x - a)^2 + .....](https://tex.z-dn.net/?f=f%28x%29%20%3D%20f%28a%29%20%2B%20%5Cfrac%7Bdf%7D%7Bdx%7D%28a%29%2A%28x%20-a%29%20%2B%20%281%2F2%21%29%5Cfrac%7Bd%5E2f%7D%7Bdx%5E2%7D%28a%29%2A%28x%20-%20a%29%5E2%20%2B%20.....)
Here we have:
f(x) = 4*cos(x)
a = 7*pi
then, let's calculate each part:
f(a) = 4*cos(7*pi) = -4
df/dx = -4*sin(x)
(df/dx)(a) = -4*sin(7*pi) = 0
(d^2f)/(dx^2) = -4*cos(x)
(d^2f)/(dx^2)(a) = -4*cos(7*pi) = 4
Here we already can see two things:
the odd derivatives will have a sin(x) function that is zero when evaluated in x = 7*pi, and we also can see that the sign will alternate between consecutive terms.
so we only will work with the even powers of the series:
f(x) = -4 + (1/2!)*4*(x - 7*pi)^2 - (1/4!)*4*(x - 7*pi)^4 + ....
So we can write it as:
f(x) = ∑fₙ
Such that the n-th term can written as:
![fn = (-1)^{2n + 1}*4*(x - 7*pi)^{2n}](https://tex.z-dn.net/?f=fn%20%3D%20%28-1%29%5E%7B2n%20%2B%201%7D%2A4%2A%28x%20-%207%2Api%29%5E%7B2n%7D)
Answer:
2(2.5x+2)
Step-by-step explanation:
you do distributive property