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3 years ago

I need some help with my lesson pleaseee

Mathematics

2 answers:

andrezito [222]3 years ago

5 0

It is the second choice

IgorLugansk [536]3 years ago

4 0

We can that the line intercepts at ( 0 ,4 ). This means that the y-intercept is 4. Now, we get two points (usually in whole numbers to make things easy). Two good points to use to get the slope is ( 0 , 4 ) and ( 1 , 1) . We now plug it into the Slope Formula which is ∆y (change of y) / ∆x (change of x) . We get ( 1 - 4) / ( 1 - 0 ) . We now simplify it:
- 3 / 1 = - 3
We now know that the slope is - 3.
We can now plug it into the y-intercept equation which is y = mx + b, where m equals the slope and b equals the y-intercept.

We now have y = -3x + 4 which is still not the answer. We now look to see if the line is dashed or if it is solid. It is dashed, meaning that it is now either < or > . We now look again at the graph to see if the line intercepts above the dashed line or below. It is below, meaning that the answer is y < -3x + 4 .

Tip: A nice trick to do is plug in some x numbers into the function and see if it stays true on the graph and the function. If we had a 180° line going straight from left to right and already have created the function, but do not know which inequaltiy symbol to use. See which inequality symbol is true in both the function and graph.
I hope this helped you. :D

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Refer to scenario 4. assume that the profit equation is $110x1 + $150x2 what is the profit at corner point (0, 30)?

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3 years ago

Rachel tutors English. for each hour that she tutors, she earns 50 dollars. Let E be her earnings (in dollars) after tutoring fo

n200080 [17]

Answer:

a. E = 50 H b. 950 dollars

Step-by-step explanation:

a. Since Rachel tutors English for 50 dollars for each hours, her rate is 50 dollar per hour. If she tutors for time, H hours, Her earning E = rate × time = 50 × H

E = 50H.

b. If Rachel's earnings after tutoring for 19 hours is gotten by substituting H = 19 into the equation for the earnings, E.

So, E = 50H

E = 50 × 19

E = 950 dollars.

So, Rachel's earnings after 19 hours is 950 dollars.

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3 years ago

Is the expression 8 x 85 equivalent to (8 X 835? Explain. pls help I'm dying lol

Varvara68 [4.7K]

$8 \times 835 = 6680$

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2 years ago

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Solve ln(6x-1) = -4 for x

Reika [66]

Answer: Isolate the variable by dividing each side by factors that don't contain the variable.

Exact Form:

−

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Step-by-step explanation:

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2 years ago

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Imaginá que tenés 125 dados cúbicos del mismo tamaño ¿Cuantos dados de altura tiene el cubo de mayor tamaño que podés armar apil

kumpel [21]

Answer:

(i) Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

Step-by-step explanation:

(i) Sabemos por la Geometría Euclídea del Espacio que un cubo es un sólido regular con 6 caras cuadradas y longitudes iguales. Cada dado tiene un volumen de 1 dado cúbico y 125 dados dan un volumen total de 125 dados cúbicos.

El volumen de un cubo está dado por la siguiente fórmula:

$V = L^{3}$

Donde:

$L$ - Longitud de la arista, medida en dados.

$V$ - Volumen del cubo, medido en dados cúbicos.

Ahora, necesitamos despejar la longitud de la arista para calcular la altura máxima posible:

$L = \sqrt[3]{V}$

Dado que $V = 125\,dados^{3}$ , encontramos que la altura del cubo de mayor tamaño sería:

$L =\sqrt[3]{125\,dados^{3}}$

$L = 5\,dados$

Debemos apilar 5 dados para construir el cubo de mayor tamaño.

(ii) El área cuadrada formada por cubos está determinada por la siguiente fórmula:

$A = L^{2}$

Donde:

$L$ - Longitud de arista, medida en dados.

$A$ - Área, medida en dados cuadrados.

Puesto que la longitud de arista se basa en un conjunto discreto, esto es, el número de dados disponibles, debemos encontrar el valor máximo de $L$ tal que no supere 125 y de un área entera. Es decir:

$L \leq 125\,dados$

Si cada cubo tiene un área de 1 dado cuadrado, entonces un cuadrado conformado por 125 dados tiene un área total de 125 dados cuadrados. Entonces:

$L^{2}< 125\,dados^{2}$

Esto nos lleva a decir que:

$L < 11.180\,dados$

Entonces, la longitud máxima del cuadrado con la mayor cantidad de cubos posible es de 11 dados. El número total requerido de cubos es el cuadrado de esa cifra, es decir:

$n = (11\,dados)^{2}$

$n = 121\,dados$

Se necesita 121 dados cuadrados para formar el cuadrado con la mayor cantidad de dados posibles, quedando 4 dados sobrantes.

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3 years ago