Question

What is the equation of the line perpendicular to the line y=3x+2 and passing through the point (3, -4)

Answer 1

Answer:

D: y= -(1/3)x -3

Step-by-step explanation:

$(3, -4)=(x,y)\\y=3x+2\\\\m_1 =3\\In\: perpendicular\: line ;\\\\m_2 = \frac{-1}{m_1} \\m_2 = \frac{-1}{3} \\m_2 = -1/3\\\\Substitute \:new\:values\:into\: ;y=mx+b\\\\-4 = -\frac{1}{3} (3) + b\\-4 = -1 +b\\-4+1 =b\\-3 =b\\Substitute \:new\:values\:into\: ;y=mx+b\\y =-\frac{1}{3}x -3$