***The complete question is: Let f(x)= sqrt 6x and g(x)=x+3 smallest number that is in the domain of <em>f(g(x))</em>***
Answer: The <em>smallest number that is in the domain is </em><em>-3</em>.
Explanation:
Given functions:
To find f(g(x)), put g(x) in f(x) as follows:
As (6x+18) is in square-root (and square-root of a negative number is an imaginary value), therefore, the domain should be the following:
Therefore, the domain is [-3, +∞).
So the <em>smallest number that is in the domain is </em><em>-3</em>.