Question

Boyle’s law states that the volume of a gas varies inversely with applied pressure. A helium balloon has a volume of 22 cubic meters at sea level where the air pressure is 1 atmosphere. The balloon is released and rises to a point where the air pressure is only 0.8 atmosphere. What is the volume at this height in cubic meters?

Answer 1

Answer:

Volume, V₂ = 27.5 m³

Step-by-step explanation:

According to Boyle's law, the volume of a gas varies inversely with applied pressure.

i.e. $V\propto\dfrac{1}{P}$

or $V_1P_1=V_2P_2$

V₁ = 22 m³

P₁ = 1 atm

P₂ = 0.8 atm

We have to find V₂ as :

$V_2=\dfrac{V_1P_1}{P_2}$

$V_2=\dfrac{22\ m^3\times 1\ atm}{0.8\ atm}$

$V_2=27.5\ m^3$

Hence, the volume at the height is 27.5 m³

Answer 2

Boyle's Law
P1 • V1 = P2 • V2

Solving that for Volume
V2 = (P1 • V1) / P2
V2 = (1 • 22) / .8
V2 = 27.5

Source:
http://www.1728.org/boyle.htm