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mojhsa [17]
3 years ago
12

Boyle’s law states that the volume of a gas varies inversely with applied pressure. A helium balloon has a volume of 22 cubic me

ters at sea level where the air pressure is 1 atmosphere. The balloon is released and rises to a point where the air pressure is only 0.8 atmosphere. What is the volume at this height in cubic meters?
Mathematics
2 answers:
andrezito [222]3 years ago
6 0

Answer:

Volume, V₂ = 27.5 m³

Step-by-step explanation:

According to Boyle's law, the volume of a gas varies inversely with applied pressure.

i.e. V\propto\dfrac{1}{P}

or V_1P_1=V_2P_2

V₁ = 22 m³

P₁ = 1 atm

P₂ = 0.8 atm

We have to find V₂ as :

V_2=\dfrac{V_1P_1}{P_2}

V_2=\dfrac{22\ m^3\times 1\ atm}{0.8\ atm}

V_2=27.5\ m^3

Hence, the volume at the height is 27.5 m³

balu736 [363]3 years ago
3 0
Boyle's Law <span>
P1 • V1 = P2 • V<span>2

Solving that for Volume
</span></span><span><span>V<span>2 = </span></span>(P1 • V1) / P2 </span>
V2 = (1 <span>• 22) / .8
V2 = 27.5

Source:
http://www.1728.org/boyle.htm

</span>
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