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Reika [66]
3 years ago
14

What's bigger 3/6 or 3/8

Mathematics
2 answers:
Zanzabum3 years ago
7 0
3/6 is bigger because it simplifies to 1/2 and 3/8 is below 1/2.
kumpel [21]3 years ago
3 0
3/6 would be bigger. A general thing to remember is the fraction with the smaller denominator ( bottom number of fraction) is usually bigger
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A regular square pyramid has base edge b, height h, and slant height l. Three expressions give the surface area, A, of this pyra
S_A_V [24]

Answer:

1/3 . Abase . height

Step-by-step explanation:

Please find attached the complete question

a square pyramid is a pyramid that has a square base.

total surface area measures the total area of the surfaces of an object

the formula 1/3 x Area of the base x height is used to calculate the volume of the pyramid and not the surface area

7 0
2 years ago
Simplify the expression where possible.<br><br> (3b 3) 4<br><br> .
goblinko [34]

Answer: 36b

Step-by-step explanation:

3•3=9 add the 9

9b • 4

8 0
3 years ago
Given the coordinates S(-3,6) and T(4, -8). Find the equation of the line that passes through the two points and write the equat
baherus [9]

Answer:

m=slope

y= intercept

m=y2-y1 /x2-x1     -8  - 6= -14

                              4- -3 =   7

                                        -14/7 a 2 is your slope

y=2x=b

Now we find for X

choose a y from one of your points :  lets use 6 Plug 6 in for y s(-3,6)

y=2x+b

6=2(-3) +b

now solve for b

6= -6 + b  

now add 6 to both sides to get b alone

6+6 =6+-6 +b

12=b

now write you equation out  y=2x =12

Step-by-step explanation:  

hope that helps

8 0
3 years ago
A 30cm ruler sometimes measures inches on the other side.
Alisiya [41]

1inch = 2.5cm

∆ 30cm

<h3>1inch x 30cm \2.5cm =? </h3>

5cm =2inch

  1. so 30cm=12inch
4 0
2 years ago
Answer the question in the picture
Svet_ta [14]
<h3>Answer:</h3>
  • left picture (bottom expression): -cot(x)
  • right picture (top expression): tan(x)
<h3>Step-by-step explanation:</h3>

A graphing calculator can show you a graph of each expression, which you can compare to the offered choices.

_____

You can make use of the relations ...

... sin(a)+sin(b) = 2sin((a+b)/2)cos((a-b)/2)

... cos(a)+cos(b) = 2cos((a+b)/2)cos((a-b)/2)

... cos(a)-cos(b) = -2sin((a+b)/2)sin((a-b)/2)

Then you have ...

\dfrac{\cos{2x}-\cos{4x}}{\sin{2x}+\sin{4x}}=\dfrac{2\sin{3x}\sin{x}}{2\sin{3x}\cos{x}}=\dfrac{\sin{x}}{\cos{x}}=\tan{x}

and ...

\dfrac{\cos{2x}+\cos{4x}}{\sin{2x}-\sin{4x}}=\dfrac{2\cos{3x}\cos{x}}{-2\cos{3x}\sin{x}}=\dfrac{-\cos{x}}{\sin{x}}=-\cot{x}


6 0
4 years ago
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