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attashe74 [19]
3 years ago
15

Given sina=6/7 and cosb=-1/6, where a is in quadrant ii and b is in quadrant iii

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0
I dont understand that problem
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What does this problem equal?show your work.<br><br>-12(k+4)=60
HACTEHA [7]
Hey there!

First, divide both sides by 12
-12(k+4)/-12= 60/-12 and you would getk+4=5
Now subtract 4 from both sides

k+4-4= 5-4

k=-9
3 0
4 years ago
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0.005680 is how much greater than 0.0004359
Lesechka [4]

Answer:

Answer is: 0.0052441

8 0
3 years ago
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Y=+/-√bx+c+d Use the inverse of the function y= x2 -18x to find the unknown values.<br>​
ozzi

Answer:

a=1

b=81

c=9

Step-by-step explanation:

3 0
3 years ago
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Find LCM of 9-p^2 and p^2+3p​
snow_lady [41]

Answer:

(3+p)

Step-by-step explanation:

solution

first expression=9-P^2

=3^2 - P^2

=(3+P) (3-p)

second expression=p^2 + 3p

= p(3+p)

Therefore lCM= (3+p)

3 0
3 years ago
Solve<br> 7x+2y=16<br> 5x-2y=20<br> x= y= <br><br> (3 marks)
sasho [114]
X=3 and y=-5/2. Here is why, when we do 7x+5x that gives us 12x. -2y+2y=0 and then we have 16 plus 20 which gives us 36. Now we gotta isolate x which right now we have 12x=36. Therefore divide by 12 to get x alone, which 36 divided by 12 is equal to 3. X=3. Plug it back into the equation, 7(3)=21 plus 2y=16. Subtract 21 from both sides 16-21 is equal to -5. Then 2y=-5 divide by 2 on both sides you will have -5/2=y or y=-5/2. Hope this helps!
8 0
3 years ago
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