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MArishka [77]
3 years ago
15

A jewelry box containes 3 rings, 7 necklaces, 4 earrings, 5 braceletes and 1 tiara. If 1 piece of jewlery is selected at radom,

which two statements are true?
a it is just as likely as not that a ring or necklace will be selected.
b It is impossible that a tiara will be selected.
c It is certain that a necklace will be selected.
d It is likely that earrings or a bracelet will be selected.
e it is unlikely that a tiara will be selected.
Mathematics
2 answers:
Brums [2.3K]3 years ago
6 0

Answer:

C and D

Step-by-step explanation:

Hope this helps!

Anestetic [448]3 years ago
6 0

Answer:

A and E

Step-by-step explanation:

A because there are 3 rings and 7 necklaces, so there is a high chance they will be picked. But because there are earrings, braceletes, and one tiara, its not 100% cirtain that the rings or necklaces will be picked.

E because there is only one tiara. There are way more of all the other pieces of jewelry. But if its a choice to be picked there is a small chance it could be chosen.

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Use the table to work out the values of a , b , c , and d .​
slavikrds [6]

Answer:

a = 10, b = 6, c = 2, d = 0

Step-by-step explanation:

Substitute the appropriate values of x into the equation and evaluate

x = - 3 : y = 4 - 2(- 3) = 4 + 6 = 10 → a

x = - 1 : y = 4 - 2(- 1) = 4 + 2 = 6 → b

x = 1 : y = 4 - 2(1) = 4 - 2 = 2 → c

x = 2 : y = 4 - 2(2) = 4 - 4 = 0 → d

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Answer:

D. The player skates 12 m forward and then skates 12 m in the opposite direction.​

Step-by-step explanation:

The player skates 12 m forward then back 12 m which means he is back to his starting point. :)

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A 4-lb. force acting in the direction of (vector) 4,-2 moves an object just over 7ft from point (0,4) to (5,-1). Find the work d
Tcecarenko [31]

To solve this problem, we have to find the net displacement and the net force and the multiply the dot product together and get the work done.

The work done on moving the object is 27ft*lbs

<h3>Work done in moving the object from point A to point B</h3>

To find the work done on this object, let's find the net force on the object.

Data;

  • force = 4lb
  • direction = 4, -2
  • displacement = 7ft
  • direction = (0, 4) to (5,1)

The unit vector of the force is

\sqrt{4^2 +(-2)^2} =\sqrt{16 + 4} = \sqrt{20}

\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} }

The net force acting on the object is

F = 4(\frac{4}{\sqrt{20} }, \frac{-2}{\sqrt{20} })\\F= (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } )

The displacement on the object is 7ft through (0,4) to (5, -1)

The unit vector on displacement is

\sqrt{5^2 + (-1-4)^2} = \sqrt{25+25} = \sqrt{50}

\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }

The net displacement will be

7(\frac{5}{\sqrt{50} }, \frac{-5}{\sqrt{50} }) = \frac{35}{\sqrt{50} }, \frac{-35}{50}

The work done will be F.d

w = f. d \\

w = (\frac{16}{\sqrt{20} }, \frac{-8}{\sqrt{20} } ) * \frac{35}{\sqrt{50} }, \frac{-35}{50}\\w = 17.71+ 8.854\\w = 26.567 = 27ft*lbs

The work done on moving the object is 27ft*lbs

Learn more on work done on an object here;

brainly.com/question/26152883

#SPJ1

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2 years ago
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