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scoray [572]
4 years ago
13

What the square root of 50/ 250 (rounded to 2 decimal places)? * 0.45 0.44 0.47 0.46

Mathematics
1 answer:
Mandarinka [93]4 years ago
5 0

Answer:

Root = 0.44

Step-by-step explanation:

Required

Determine the square root of \frac{50}{250}

Start by simplifying the fraction

Digit = \frac{50}{250}

Divide the numerator and denominator by 50

Digit = \frac{1}{5}

Next, determine the square root;

Root = \sqrt{\frac{1}{5}}

Split the squarer root

Root = \frac{\sqrt{1}}{\sqrt{5}}

Root = \frac{1}{\sqrt{5}}

Rationalize

Root = \frac{1}{\sqrt{5}} * \frac{\sqrt{5}}{\sqrt{5}}

Root = \frac{\sqrt{5}}{5}

Root = \frac{2.2360679775}{5}

Root = 0.4472135955

Root = 0.44 --- <em>Approximated</em>

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Equation of the line:

y = -0.5x + 2

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Solve the following triangle. Given A=51 degrees b=40 c=45
STALIN [3.7K]

Answer:

a=36.87\ units

B=57.47^o

C=71.53^o

Step-by-step explanation:

step 1

Find the length side a

Applying the law of cosines

a^2=b^2+c^2-2(b)(c)cos(A)

substitute the given values

a^2=40^2+45^2-2(40)(45)cos(51^o)

a^2=1,359.4466

a=36.87\ units

step 2

Find the measure of angle B

Applying the law of sines

\frac{a}{sin(A)} =\frac{b}{sin(B)}

substitute the given values

\frac{36.87}{sin(51^o)} =\frac{40}{sin(B)}

sin(B)=\frac{sin(51^o)}{36.87}{40}

B=sin^{-1}(\frac{sin(51^o)}{36.87}{40})=57.47^o

step 3

Find the measure of angle C

Remember that the sum of the interior angles in any triangle must be equal to 180 degrees

so

A+B+C=180^o

substitute the given values

51^o+57.47^o+C=180^o

108.47^o+C=180^o

C=180^o-108.47^o=71.53^o

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4 years ago
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