Hello from MrBillDoesMath!
Answer:
x = 80/3 ( 26 2/3)
y = 11
Discussion:
Step 1:
-2 + y = 9 => add 2 to both sides
2 + -2 + y = 9 +2 =>
y = 11
Step 2:
Substitute y = 11 (from Step 1) into
3x - 7y = 3 =>
3x - 7(11) = 3 => y = 11 from Step 1
3x - 77 = 3 => add 77 to both sides
3x - 77 + 77 = 3 + 77 =>
3x = 80 =>
x = 80/3
Thank you,
MrB
Answer:
The answer to your question is the third histogram
Step-by-step explanation:
What we must check in a histogram is that the x-axis is represented the intervals and in the y-axis is represented the frequency.
The first histogram is incorrect just by observing the first bar, we notice that the correct frequency from 0 to 4 is 3, not 14. This histogram is incorrect.
Also, the second histogram is incorrect, the frequency of the first category is 3, not 12. This histogram is wrong.
The third histogram is correct because all the bars are in agreement with their frequencies.
The last histogram is incorrect, for example, the last frequency is 12, not 3.
The square of a binomial expands as follows:
Expanding all the binomials, we have
Sum like terms:
Simplify terms appearing on both sides:
Move all terms involving k to the left and all numbers to the right:
Divide both sides by -20:
Answer:
terrence will have to play 2900
Step-by-step explanation:
80% * 14500
14500-11600
2900
