Answer:
Height of the cone is thrice the height of the cylinder
Step-by-step explanation:
Let 'h' b e the height of the cylinder and 'H' be the height of the cone.
Volume of cylinder = base area × h
Volume of cone = 1/3 (base area)×H
Since the volumes are equal with same base areas,
base area × h = 1/3 (base area)×H
h = H/3
Or,
3h = H
Answer:
b=n+2
Step-by-step explanation:
I just know this answer
Have a good day/night UωU
Answer:
42.2
Step-by-step explanation:
all you have to do is add up the number just how they are
Answer: 12 students
Step-by-step explanation:
Let X and Y stand for the number of students in each respective class.
We know:
X/Y = 2/5, and
Y = X+24
We want to find the number of students, x, that when transferred from Y to X, will make the classes equal in size. We can express this as:
(Y-x)/(X+x) = 1
---
We can rearrange X/Y = 2/5 to:
X = 2Y/5
The use this value of X in the second equation:
Y = X+24
Y =2Y/5+24
5Y = 2Y + 120
3Y = 120
Y = 40
Since Y = X+24
40 = X + 24
X = 16
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Now we want x, the number of students transferring from Class Y to Class X, to be a value such that X = Y:
(Y-x)=(X+x)
(40-x)=(16+x)
24 = 2x
x = 12
12 students must transfer to the more difficult, very early morning, class.
1.99 divided by 12 would give u about 0.66$
