The perimeter of the triangle would be B)18. the triangle's sides are equal and you can tell by the single lines on each side symbolizing that all the sides are equal. To find perimeter, you have to add all sides together, and in this case it is 6. When 6 is added three times, it equals 18, which is the answer.
84 in I believe? (Im sorry im not much help)
Answer:
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Step-by-step explanation:
for
I= ∫x^n . e^ax dx
then using integration by parts we can define u and dv such that
I= ∫(x^n) . (e^ax dx) = ∫u . dv
where
u= x^n → du = n*x^(n-1) dx
dv= e^ax dx→ v = ∫e^ax dx = (e^ax) /a ( for a≠0 .when a=0 , v=∫1 dx= x)
then we know that
I= ∫u . dv = u*v - ∫v . du + C
( since d(u*v) = u*dv + v*du → u*dv = d(u*v) - v*du → ∫u*dv = ∫(d(u*v) - v*du) =
(u*v) - ∫v*du + C )
therefore
I= ∫u . dv = u*v - ∫v . du + C = (x^n)*(e^ax) /a - ∫ (e^ax) /a * n*x^(n-1) dx +C = = (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C
I= (x^n)*(e^ax) /a - n/a ∫ (e^ax) *x^(n-1) dx +C (for a≠0)
Answer:
87.72%
Step-by-step explanation:
Data provided in the question:
Design capacity of the system = 1900 students per semester
Effective capacity = 90% of design capacity
Actual number of students = 1500
Now,
Efficiency = [ [ Actual capacity ] ÷ [ Effective capacity ] ] × 100%
also,
Effective capacity = 90% of 1900
= 0.90 × 1900
= 1710
Efficiency = [ 1500 ÷ 1710 ] × 100%
= 0.8772 × 100%
= 87.72%
