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Elena-2011 [213]

3 years ago

8

Hector is rewriting the expression 7 Superscript 11 in expanded form. How many terms will be multiplied in his rewritten express

ion?

2 answers:

Korolek [52]3 years ago

8 0

Answer:

Step-by-step explanation

The screenshot is proof

-BARSIC- [3]3 years ago

3 0

Answer:11

Step-by-step explanation:just took the quiz <3

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Can someone help me I need the answers to 1-4 ty!!

lubasha [3.4K]

1. x=-3 y=4 2. x=5/2 y=15/2 3. x=9/5 y=-36/5 4. x=-2 y=1

8 0

3 years ago

Please help!!! asap!!!

quester [9]

Answer:

x = 11 cos 22 = 11 * .927 = 10.2

5 0

2 years ago

A real estate agent has 19 properties that she shows. She feels that there is a 30% chance of selling any one property during a

netineya [11]

Answer:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=19, p=0.3)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want to find this probability:

$P(X \geq 5)$

And we can use the complement rule:

$P(X \geq 5)=1-P(X$

We can find the individual probabilities:

$P(X=0)=(19C0)(0.3)^0 (1-0.3)^{19-0}=0.00114$

$P(X=1)=(19C1)(0.3)^1 (1-0.3)^{19-1}=0.0092$

$P(X=2)=(19C2)(0.3)^2 (1-0.3)^{19-2}=0.0358$

$P(X=3)=(19C3)(0.3)^3 (1-0.3)^{19-3}=0.0869$

$P(X=4)=(19C4)(0.3)^4 (1-0.3)^{19-4}=0.1491$

And replacing we got:

$P(X \geq 5) = 1-[0.00114+0.009282+0.0358+0.0869+0.149]= 0.7178$

4 0

3 years ago

The sum of two numbers is

bekas [8.4K]

Okay you have 2 sum unknow lets call them X+Y

so X+Y=33, 4X=108

Get X by it self then plug it in 4X=108

X=-Y+33
4(-y+33)= 108
-4y+132=108 Then subtract the 132
-4y=-24 Y=6 then to find X subtract 33-6=27
Y=6 X=27 if you check it works out

3 0

3 years ago

Read 2 more answers

Two angles are supplementary.one anglemeasures 15 degrees more than 4 times the other. what is the measure of the larger angle i

tatiyna

X + (4x+15) = 180
5x+15=180
5x=165
x=33
4(33)+15=147. (Or you could subtract 33 from 180)
Check answer: 33+147=180 yes

6 0

3 years ago