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Elena-2011 [213]

3 years ago

8

Hector is rewriting the expression 7 Superscript 11 in expanded form. How many terms will be multiplied in his rewritten express

ion?

2 answers:

Korolek [52]3 years ago

8 0

Answer:

Step-by-step explanation

The screenshot is proof

-BARSIC- [3]3 years ago

3 0

Answer:11

Step-by-step explanation:just took the quiz <3

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Compare the triangles and determine whether they can be proven congruent by SSS, SAS, ASA, AAS, or HL. If not, type "NONE".

Komok [63]

Answer:

SAS

Step-by-step explanation:

6 0

3 years ago

Use the Chain Rule to find the indicated partial derivatives. z = x^4 + xy^3, x = uv^4 + w^3, y = u + ve^w Find : ∂z/∂u , ∂z/∂v

k0ka [10]

I'll use subscript notation for brevity, i.e. $\frac{\partial f}{\partial x}=f_x$ .

By the chain rule,

$z_u=z_xx_u+z_yy_u$

$z_v=z_xx_v+z_yy_v$

$z_w=z_xx_w+z_yy_w$

We have

$z=x^4+xy^3\implies\begin{cases}z_x=4x^3+y^3\\z_y=3xy^2\end{cases}$

and

$\begin{cases}x=uv^4+w^3\\y=u+ve^w\end{cases}\implies\begin{cases}x_u=v^4\\x_v=4uv^3\\x_w=3w^2\\y_u=1\\y_v=e^w\\y_w=ve^w\end{cases}$

When $u=1,v=1,w=0$ , we have

$\begin{cases}x(1,1,0)=1\\y(1,1,0)=2\end{cases}\implies\begin{cases}z_x(1,2)=12\\z_y(1,2)=12\end{cases}$

and the partial derivatives take on values of

$\begin{cases}x_u(1,1,0)=1\\x_v(1,1,0)=4\\x_w(1,1,0)=0\\y_u(1,1,0)=1\\y_v(1,1,0)=1\\y_w(1,1,0)=1\end{cases}$

So we end up with

$\boxed{\begin{cases}z_u(1,1,0)=24\\z_v(1,1,0)=60\\z_w(1,1,0)=12\end{cases}}$

3 0

3 years ago

An electrician charges $40 to come to your house. She also charges $55 for each hour that she works. The electrician charges you

laiz [17]

The answer for this problem is two remainder seven

4 0

3 years ago

Hellpp and thanks!!

kherson [118]

Answer:

c = 4n

Step-by-step explanation:

5 0

3 years ago

Find the GCF of 14a and 28ab

likoan [24]

<u><em>Answer:</em></u>

14a

<u><em>Explanation:</em></u>

The greatest common factor is defined as the largest number by which the two given terms can be divided

The first given term is 14a, let's leave it as it is for now

The second given term is 28ab, this term can be rewritten as:

2 * 14a * b

We can note that the 14 a is the largest factor by which the two terms can be divided

This means that the GCF of the two given terms is 14a

Hope this helps :)

6 0

3 years ago

Read 2 more answers