Dy/dx=2x+2
So velocity will be zero when 2x+2=0, x=-1
Since d2y/dx2=2, it has a constant positive acceleration of 2, so that when dy/dx=0 it is at an absolute minimum value for f(x), which is also the vertex.
y(-1)=1-2+3=2
So the vertex is at (-1,2), which is an absolute minimum so the parabola opens upwards.
And by symmetry we can say that f(0)=f(-2)=3 so you have another two points that you can see (-2,3) and (0,3)
Answer:
C
Step-by-step explanation:
First of all,
- if the line goes Upward (from left to right), it is sloping upward and the correlation coefficient would be POSITIVE.
- If the line goes Downward (from left to right), it is sloping downward and the correlation coefficient would be NEGATIVE.
Since, from the graph we can see that the line is sloping upward, we know the correlation coefficient would be POSITIVE, so we can immediately eliminate choices A & B.
Now, the closer the correlation coefficient value is to 0, the less steep the line is. The closer it is to 1, the more steeper it is.
Looking at the graph, it isn't that flat, it is quite steep. So the correlation coefficient would be 0.8, NOT 0.1
So, answer choice C is right.