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3 years ago

Trigonometry… need help... 25 points

Mathematics

1 answer:

oksian1 [2.3K]3 years ago

7 0

Answer:

Step-by-step explanation:

you do tan(22)x203

=82

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Given the system

Irina-Kira [14]

we have

y > -2 x + y < 4

using a graph tool

see the attached figure

The shaded area is the solution of the system

Part 1) Name an ordered pair that is a solution to this system and explain how you know that this is a solution point

Let

A ( -40,20)

The point A is solution of the system because the point lie on the shaded area

Check

If the point A is solution of the system must satisfy both system inequalities

point A

x=-40

y=20

substitute

y > -2-------> 20 > -2-------> is ok

x + y < 4----> -40+20 < 4-----> -20 < 4-----> is ok

therefore

the answer Part 1) is

The point A is a solution of the system

Part 2) Name an ordered pair that is not a solution to the system and explain how you know that it is not a solution

Let

B(20,20)

The point B is not solution of the system because the point not lie on the shaded area

Check

If the point B is not solution of the system must not satisfy both system inequalities

point B

x=20

y=20

substitute

y > -2 -------> 20 > -2-------> is ok

x + y < 4---->20+20 < 4-----> 40 < 4------> is not ok

therefore

the answer part 2) is

The point B is not a solution to the system

6 0

3 years ago

8. Is the following statement true or false? Justify your conclusion. If a and b are nonnegative real numbers and a + b =0, then

atroni [7]

Answer:

If $a + b = 0$ then $a = 0$ and $b =0$

a | b | a + b (answer)

0 | 0 | 0

0 | 1 | 1

0 | 2 | 2

1 | 0 | 1

2 | 0 | 2

1 | 1 | 2

2 | 1 | 3

Step-by-step explanation:

Considering the following conditions for the real numbers:

$a\geq 0\\b\geq 0$

Following the rules of these in-equations, it is possible to deduce:

$a + b \geq 0$

Then, if the proposed statement is:

$a + b = 0$

The conditions above shall comply the requirements established, but first, analyzing the statement:

If $a \geq 0$ and $b \geq 0$ then $a + b \geq a$ , $a + b \geq b$ and $a + b \geq 0$ .

If $a = 0$ and b a non negative real number, then $a + b \geq b$ , but because to $a = 0$ , then $a + b = b$ . Due to the commutative property of sums, the same behavior will be presented if $b = 0$ and a a non negative real number.

According to that, if $a + b = 0$ , then $a = 0$ and $b = 0$ .

7 0

3 years ago

Please help me out!!!!!

Gnoma [55]

The last answer: 2 or 0

Explanation:

When you graph this function, it crosses the x-axis once. In other words, that means there is only 1 real zero and 2 imaginary complex zeros. In addition, imaginary solutions always come in pairs, so there can’t be a odd number of them such as 3.

8 0

3 years ago

which equation shows the point slope form of the line that passes through (3,2) and has a slope of 1/3

gavmur [86]

Answer:

y=1/3x+1

Step-by-step explanation:

y=mx+b

y=1/3x+b

2=1/3(3)+b

2=1+b

1=b

y=1/3x+1

8 0

3 years ago

What is |-8| + |6| ?

Irina18 [472]

|-8| + |6| should be 14

5 0

3 years ago

Read 2 more answers