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BlackZzzverrR [31]
3 years ago
15

Solve the following equation for h. r+3Q/h=t

Mathematics
1 answer:
Arada [10]3 years ago
4 0

Answer:

             \bold{h=\dfrac{3Q}{t-r}}

Step-by-step explanation:

\bold{r+\frac{3Q}h=t}\\-r\qquad\ -r\\\bold{\frac{3Q}h=t-r}\\\cdot h\qquad \cdot h\\ \bold{3Q=(t-r)h}\\^{\div(t-r)\quad\div(t-r)}\\\bold{\dfrac{3Q}{t-r}=h}

Or, if you mean (r+3Q)/h=t:

\bold{\frac{r+3Q}h=t}\\{}\ \ \cdot h\quad\ \cdot h\\\bold{r+3Q=ht}\\{}\ \ \div t\qquad \div t\\\bold{\dfrac{r+3Q}{t}=h}\\\\\bold{h=\dfrac{r+3Q}{t}}

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the coordinates of point Q that is 2/3 of the way along the directed segment from R(-7,-2) to S(2,4)

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