The probability that the aircraft is overloaded is 97.98%, which means the pilot should take the action.
In a Normal distribution with mean ц and standard deviation σ, the z-score of a measure x is given by:
Z = X-ц / σ
· It measures how many standard deviations the measure is from the mean.
· After finding Z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.
· By the Central Limit Theorem, the sampling distribution of sample means of the size n has standard deviation σ
σ = σ /
σ is standard deviation
n is the sample size.
Given that the mean and the standard deviation of the population is 176.1 lb and 35.4 respectively.
⇒ ц = 176.1 and σ = 35.4
For a sample of 43 passengers, we have
n = 43
σ = 
σ = 5.398
Z = X-ц / σ
Z = 
Z = -2.05 has p- value of 0.9798
The probability that the aircraft is loaded is
1 - p-value of Z
1 - 0.0202 = 0.9798
The probability that the aircraft is overloaded is 97.98%
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86.3 / 30 = 2.876
Therfore the answer is D $2.88
Since is a positive a value (4) we know that the graph opens upward. -5 represents how far up or down the “vertex” is of the absolute value graph. This means that the range is -5
Answer:
-39
Step-by-step explanation:
||u|| = sqrt(5² + (-12)²)
= sqrt(25 + 144)
= sqrt(169)
= 13
||cu|| = c ||u||
c = -3
c ||u|| = -3 × 13 = -39