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densk [106]
3 years ago
15

Find a pair of polar coordinates for the point with rectangular coordinates (5, –5).

Mathematics
1 answer:
Elanso [62]3 years ago
7 0

Answer:

(5*sqrt(2), 5pi/4)

Step-by-step explanation:

In Polar coordinates, tan(theta)=y/x and r=sqrt(x^2+y^2)

tan(theta)=-5/5=-1. Theta=5pi/4

r=sqrt(5^2+5^2)=5*sqrt(2)

Hence the Polar coordinate is (5*sqrt(2), 5pi/4)

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can someone pls help me? i have no idea what to do. pls show the work steps for the questions. i will mark u as
tiny-mole [99]

Ok, so the question is based on geometric progression. Remember, the formula for calculating the nth-term of a geometric progression is: a*r^{n-1}. The a in the expression stands for the 1st term of the sequence, and r is the common ratio of the elements of the sequence. Now let's take a look at the problem.

"A ping pong ball has a 75% rebound ration". We can infer that our common ratio, r, is 75% which is 0.75.

"When you drop it from a height of k feet...", this means the first height you drop it from, a.k.a, the first term.

Now going back to the expression, the nth-term = a*r^{n-1}, we can substitute our common ration, 0.75 with r, and our 1st term, k, with a. This becomes: k * 0.75^{n-1}. This becomes our expression.

a. The highest height achieved by the ball after six bounces. Our nth-term here is 6, so let's use our expression to find the 6th term. n_{6} = 235 * 0.75^{6-1} = 235*0.75^{5} = 235*0.2373 = 55.7655ft

b. The total distance travelled by the ball when it strikes the ground for the 12th time. This involves the use of the sum of elements in the geometric progression. The formula for that is \frac{a(1 - r^{n})}{1-r}, provided that r is less than 1, which it is in this case, since 0.75 is less than one. Our nth-term here is 12, so we substitute.

\frac{235(1-0.75^{12})}{(1-0.75)} = 910.2242ft

6 0
3 years ago
Which values could be the values of x and y? ​
Brrunno [24]

Answer:

x: 3/4, 1 1/4, x

y:6 1/4, 7 3/4, y

Step-by-step explanation:

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3 years ago
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natta225 [31]
It is impossible because it's base is not circular. A solid of revolution is <span>obtained by rotating a </span>plane curve<span> around some </span>straight line, that is, <span>the </span>axis of revolution that lies on the same plane. The closest to a square pyramid applying this concept is by rotating a right triangle around the opposite or adjacent side (the axis), but the shape that you get is a straight circular cone. 
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3 years ago
GIVING BRAINLIST TO ANYONE WHO SOLVES ANY QUESTION &lt;3
brilliants [131]

Answer:

Mild-Level 1: X=10

Medium-Level 2: X=21

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Step-by-step explanation:

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7 0
3 years ago
What is the best result for h?
Kryger [21]

Answer: First option.

Step-by-step explanation:

To solve for "h" from the given the equation S=2\pi rh+2\pi r^2, you need to:

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Then you need to apply the Division property of equality and divide both sides of the equation by 2\pi r.

Then:

S-2\pi r^2=2\pi rh+2\pi r^2-2\pi r^2\\\\S-2\pi r^2=2\pi rh\\\\\frac{S}{2\pi r}-\frac{2\pi r^2}{2\pi r}=\frac{2\pi rh}{2\pi r}\\\\\frac{S}{2\pi r}-r=h

6 0
3 years ago
Read 2 more answers
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