How many combinations are there of the five letters j, k, l, m, and n using three letters at a time?
2 answers:
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Explanation:
6(2x + 5) = 2(3x – 2)
[given]
6(2x) + 6(5) = 2(3x) + 2(-2)
12x + 30 = 6x – 4
[distributive property of equality; individually multiply each addend inside the parenthesis and simplify (distribute the terms) ]
12x + 30 = 6x – 4
–6x –6x
6x + 30 = -4
[subtraction property of equality; subtract both sides by 6x in order to keep the x term on the left side]
6x + 30 = -4
–30 –30
6x = -34
[subtraction property of equality; subtract both sides by 30 in order to keep the constant term on the right side]
6x = -34
÷6 ÷6
x = -34/6
[division property of equality; divide both sides by 6 to eliminate the coefficient of 6 in 6x in order to obtain the variable x]
x = -17/3
[GCF(greatest common factor); divide both sides by the greatest common factor until both numbers are prime (only divisible by 1 and itself]
