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3 years ago

Please help what is the length of ac rounded to the nearest hundredth

Mathematics

1 answer:

SpyIntel [72]3 years ago

8 0

Answer:

2.96

Step-by-step explanation:

cos(65) = AC/7

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-3(6 - 3k)<br>I need to Simplify the expression

sergij07 [2.7K]

Answer:

-18+9k

Step-by-step explanation:

If you use the distributive property, you get:

(-3*6) and (-3*-3k)

If you simplify each of them you get:

-18+9k

8 0

3 years ago

Read 2 more answers

A company charges a $12 fee to make a house call plus an hourly rate for labor. If the total bill for a job that takes 2.5 hours

Ilia_Sergeevich [38]

$95.75 = 12 + 2.5r
I’m 100% sure of this.

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3 years ago

cell phone provider offers a plan that costs $40 per month plus $0.20 per text message sent or received. A comparable plan cos

Orlov [11]

Answer:

the second one is the better deal

Step-by-step explanation:

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3 years ago

Given A is between Y and Z, and YA=14x, AZ=10x and YZ=12x+48, solve for x

iren [92.7K]

Answer:The answers are: 4 40 56 96.

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3 years ago

The accompanying summary data on total cholesterol level (mmol/l) was obtained from a sample of Asian postmenopausal women who w

dimulka [17.4K]

Answer:

99% CI:

$-4.637\leq\mu_v-\mu_o\leq 3.737$

Step-by-step explanation:

We have to calculate a 99%CI for the difference of means for the vegan and the omnivore.

First, we have to estimate the standard deviation

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}$

The MSE can be calculated as

$MSE=\frac{(SSE_1+SSE_2)}{df} =\frac{(n_1s_1)^2+(n_2*s_2)^2}{n_1+n_2-2}\\\\MSE=\frac{(85*1.05)^2+(96*1.20)^2}{85+96-2}=\frac{7965.56+13272.04}{179} =118.65$

The weighted sample size nh can be calculated as

$n_h=\frac{2}{1/n_1+1/n_2}=\frac{2}{1/85+1/96}=\frac{2}{0.0222} =90.16$

The standard deviation then becomes

$s_{Md}=\sqrt{\frac{2MSE}{n_h}}=\sqrt{\frac{2*118.65}{90.16}}=\sqrt{2.632} =1.623$

The z-value for a 99% confidence interval is z=2.58.

The difference between means is

$\Delta M=M_v-M_o=5.10-5.55=-0.45$

Then the confidence interval can be constructed as

$\Delta M-z*s_{Md}\leq\mu_v-\mu_o\leq \Delta M+z*s_{Md}\\\\ -0.45-2.58*1.623\leq\mu_v-\mu_o\leq -0.450+2.58*1.623\\\\-0.450-4.187\leq\mu_v-\mu_o\leq-0.450+4.187\\\\-4.637\leq\mu_v-\mu_o\leq 3.737$

8 0

3 years ago