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Ahat [919]
3 years ago
11

Does the table represent a linear or an exponential function? Explain.

Mathematics
1 answer:
leva [86]3 years ago
6 0

we can use MS excel to plot the given data and check whether the graph's trendline has an  R-squared of 1. The graph does not fit into a line but fits into an exponential function. The trendline's equation is equal to y = 4e^1.3863x where R squared is equal to 1
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What is the y-intercept of the function, y = 3x -5?
vlabodo [156]

Answer:

-5 is the y-intercept

Step-by-step explanation:

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8 0
4 years ago
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Prove that (sec theta-cos theta) ( cot theta+tan theta) = tan theta ×sec theta​
meriva

Given:

(\sec \theta \cos \theta)(\cot \theta+\tan \theta)=\tan \theta \sec \theta

To prove:

The given statement.

Proof:

We have,

(\sec \theta -\cos \theta)(\cot \theta+\tan \theta)=\tan \theta \sec \theta

Taking LHS, we get

LHS=(\sec \theta -\cos \theta)(\cot \theta+\tan \theta)

LHS=(\dfrac{1}{\cos \theta }-\cos \theta)(\dfrac{\cos \theta}{\sin \theta}+\dfrac{\sin \theta}{\cos \theta})

LHS=(\dfrac{1-\cos^2 \theta }{\cos \theta })(\dfrac{\cos^2 \theta+\sin^2 \theta}{\sin \theta\cos \theta})

LHS=(\dfrac{\sin^2 \theta }{\cos \theta })(\dfrac{1}{\sin \theta\cos \theta})          [\because \cos^2 \theta+\sin^2 \theta=1]

LHS=(\dfrac{\sin \theta }{\cos \theta })(\dfrac{1}{\cos \theta})

LHS=\tan \theta \sec \theta

LHS=RHS

Hence proved.

3 0
3 years ago
What number is one thousand more than 7,323?
sveta [45]
The answer is 701,012 hope this is rigt
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The answer is Prime.

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