The points are (-4,2) and (3,-4)
using y2-y1/x2-x1
-4-2/3-2
-6/1
slope (m) is -6
to find b part of equation (y=mx+b) plug in point value for x and y
2=-6(-4)+b (multiply -6 and -4)
2=24+b (subtract 24 over)
b=-22
final equation is y=-6x-22
Answer:
The third term is -25.
Step-by-step expanation:
d(1)=3
From this equation, we know the first term is 3.
d(n)=d(n−1)−14
This looks like a recursive formula. It is used to find the next term.
n is the variable for the term number that you are solving for.
d(n-1) is the term value before the what you are looking for.
To find the 2nd term, use the formula and substitute values known:
d(n)= d(n−1)−14
d(2) = d(2-1) - 14
d(2) = d(1) - 14
We know d(1)=3
d(2) = 3 - 14
d(2) = -11
Find the third term using the same method:
d(n) = d(n−1)−14
d(3) = d(3−1)−14
d(3) = d(2)−14
d(3) = -11 - 14
d(3) = -25
Answer: IX - 4I ≤ 4
Step-by-step explanation:
In the numer line we can see that our possible values of x are in the range:
0 ≤ x ≤ 8
And we want to find an absolute value equation such that this set is the set of possible solutions.
An example can be:
IX - 4I ≤ 4
To construct this, we first find the midpoint M of our set, in this case is 4.
Then we write:
Ix - MI ≤ IMI
Notice that i am using the minor and equal sign, this is because the black dots means that the values x = 0 and x = 8 are included, if the dots were empty dots, it would be an open set and we should use the < > signs.
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Answer:
C
Step-by-step explanation:
yeah-ya......... right?
