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MissTica
3 years ago
7

I need help please. Its 2 parts.

Mathematics
1 answer:
Bezzdna [24]3 years ago
4 0
18 is 6+n. The other one is 60 because n=60 and 60+6=66. 66 represents Chang's height.
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Find the third, eighth, and tenth terms of the sequence described by the rule.
Contact [7]

Answer:

Find the third, eighth, and tenth terms of the sequence described by the rule.

A(n) = 6 + (n − 5) 2, please help!

answer choices are:

A.

−2, 0, 2

B.

2, 12, 16

C.

−4, 6, 10

D.

−8, −6, −4

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2.0

5 votes

THANKS 3

Report

the answer is B

Step-by-step explanation:

8 0
3 years ago
Convert 0.72 repeating into a fraction
Fiesta28 [93]

0.72 repeating is the sum of a geometric series with first term 0.72 and common factor 1/100. The sum is given by:

(first term) 0.72 0.72 72

--------------------------- = --------------- = ------------ = ------------

1 - common factor 1 - 1/100 99/100 99

This 72/99 can be reduced to 8/11.

0.72 repeating can be rewritten as the fraction 8/11.


5 0
3 years ago
12 less than 7 times a number is the same as 32 less than the product of -3 and a number
kaheart [24]

7n -12 = -32 + -3n

I think this is the equation

6 0
3 years ago
!!!!! determine the function being differentiated, and the number at which its derivative is being evaluated. Where possible, ev
Genrish500 [490]

Recall that the derivative of a function f(x) at a point x = c is given by

\displaystyle f'(c) = \lim_{x\to c} \frac{f(x) - f(c)}{x - c}

By substituting h = x - c, we have the equivalent expression

\displaystyle f'(c) = \lim_{h\to0} \frac{f(c+h) - f(c)}h

since if x approaches c, then h = x - c approaches c - c = 0.

The two given limits strongly resemble what we have here, so it's just a matter of identifying the f(x) and c.

For the first limit,

\displaystyle \lim_{h\to0} \frac{\sin\left(\frac\pi3 + h\right) - \frac{\sqrt3}2}h

recall that sin(π/3) = √3/2. Then c = π/3 and f(x) = sin(x), and the limit is equal to the derivative of sin(x) at x = π/3. We have

(\sin(x))' = \cos(x)

and cos(π/3) = 1/2.

For the second limit,

\displaystyle \lim_{a\to0} \frac{e^{2a} - 1}a

we observe that e²ˣ = 1 if x = 0. So this limit is the derivative of e²ˣ at x = 0. We have

\left(e^{2x}\right)' = e^{2x} (2x)' = 2e^{2x}

and 2e⁰ = 2.

8 0
2 years ago
What is (f+g)(x)? f(x)=x^3−x g(x)=x^3+2x^2−10 Enter your answer in the box.
const2013 [10]
Combine like terms:  x^3+x^3 = 2x^3

                                                    2x^2

                                                        -x

                                                      -10
                                              -------------
                            (f+g)(x) = 2x^3 + 2x^2 - x - 10 (answer)

8 0
3 years ago
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