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frez [133]
3 years ago
6

John, Maya, and Zara have been picked to compete in the national track and field championships on behalf of their school. They c

ompeted against another local school squad. It took them 240.6 seconds to complete the task. How long did they each run if they took the same amount of time to complete the race? Calculate the answer and then solve the problem.
Mathematics
1 answer:
bagirrra123 [75]3 years ago
7 0

80.2

Step-by-step explanation:

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The Math Club bought 16 graphing calculators for $765. The TI-70 model costs $40 and
Afina-wow [57]

Answer:

They bought 5

Step-by-step explanation:

65x+40y=765

65(5)+40(11)=765

5 0
3 years ago
Use the differential equation given by dy/dx=xy/3, y&gt;0<br><br> complete the table of values
melisa1 [442]
The \dfrac{\mathrm dy}{\mathrm dx} row is filled by just plugging in the corresponding values of x and y into the ODE.

For example, when x=-1 and y=1, you have

\dfrac{\mathrm dy}{\mathrm dx}=\dfrac{xy}3\implies\dfrac{\mathrm dy}{\mathrm dx}\bigg|_{x=-1,y=1}=\dfrac{(-1)(1)}3=-\dfrac13

and so on.
6 0
3 years ago
Luke can build 2 tables in a day, and he has to build more than 18 wooden tables for a client. If he works for x days, what is t
VARVARA [1.3K]
2x > 18

2x/2 > 18/2

X > 9
6 0
3 years ago
If Fun Reads Bookstore has a ready club with a $40 fee and charges $5 per book and Cool Covers Bookstores club charges $100 fee
choli [55]

Answer:

You have to buy more than 20 books to make Cool Cover Bookstore club a better deal.

Step-by-step explanation:

Given that:

Fee charged by Fun Reads Bookstore = $40

Charges per book = $5

Let x be the number of books.

A(x) = 5x+40

Fee charged by Cool Covers Bookstore = $100

Charges per book = $2

B(x) = 2x+100

For making Cool Cover Bookstores club a better deal,

B(x) > A(x)

2x+100 > 5x+40

2x-5x > 40-100

-3x > -60

Dividing both sides by -3

\frac{-3x}{-3}>\frac{-60}{-3}\\x>20

Hence,

You have to buy more than 20 books to make Cool Cover Bookstore club a better deal.

8 0
3 years ago
Make g the subject of this relation​
zhannawk [14.2K]

Answer:

see explanation

Step-by-step explanation:

Simplify the radical

\frac{U}{\frac{1}{f}+\frac{1}{g}  }

= \frac{U}{\frac{g+f}{fg} }

= \frac{Ufg}{g+f}

Square both sides

T² = \frac{Ufg}{g+f} ( multiply both sides by (g + f) )

T²(g + f) = Ufg ( distribute left side )

T²g + T²f = Ufg ← subtract Ufg from both sides

T²g - Ufg + T²f = 0 ← subtract T²f from both sides

T²g - Ufg = - T²f ← factor out g from each term on the left side

g(T² - Uf) = - T²f ← divide both sides by (T² - Uf)

g = - \frac{T^2f}{T^2-Uf} = \frac{T^2f}{Uf-T^2}

6 0
3 years ago
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