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Marizza181 [45]
3 years ago
11

1. Find the distance between the points (1, 2) and (-2,-2).

Mathematics
1 answer:
alexandr1967 [171]3 years ago
5 0

Answer:

3

Step-by-step explanation:

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What is the answer to this inequality?<br> (x+7)&gt;80
Crank

Answer:

x > 73

Step-by-step explanation:

x+7 > 80

subtract 7 from both sides

x + 7 - 7 > 80 - 7

x > 73

-Chetan K

5 0
3 years ago
What are the solutions to the system of equations? {y=2x2+6x−10 y=−x+5
inessss [21]
Answer: x = -5, 3/2 y = 10, 7/2

Explanation:

y = 2x^2 + 6x - 10 (1)
y = - x + 5 (2)

=> 2x^2 + 6x - 10 = - x + 5
2x^2 - 7x - 15 = 0
(2x - 3)(x + 5) = 0
=> 2x - 3 = 0
2x = 3
x = 3/2
=> x + 5 = 0
x = -5

According to (2):

y = -x + 5
y = -(-5) + 5
y = 5 + 5 = 10

y = -x + 5
y = -(3/2) + 5
y = -(3/2) + 10/2
y = 7/2

3 0
3 years ago
Read 2 more answers
Y=2x+3 in ordered pairs
Iteru [2.4K]

Answer:

(0,3) , (1,5) , (2,7)

Step-by-step explanation:

4 0
3 years ago
= Homework: Section 9.6
MA_775_DIABLO [31]

Answer:

here is an an example

Step-by-step explanation:

Let x = the width of the rectangle

P = 2l + 2w

2(40) + 2x ≤ 150

80 + 2x ≤ 150

2x ≤ 70

x ≤ 35 cm

7 0
3 years ago
What is the quotient of (x3 - 3x2 + 5x – 3) = (x - 1)?
IRINA_888 [86]

Note: Consider "÷" sign instead of "=".

Given:

(x^3-3x^2+5x-3)\div (x-1)

To find:

The quotient.

Solution:

We have,

(x^3-3x^2+5x-3)\div (x-1)

It can be written as

=\dfrac{x^3-3x^2+5x-3}{x-1}

Splitting the middle terms, we get

=\dfrac{x^3-x^2-2x^2+2x+3x-3}{x-1}

=\dfrac{x^2(x-1)-2x(x-1)+3(x-1)}{x-1}

Taking out the common factor (x-1), we get

=\dfrac{(x-1)(x^2-2x+3)}{x-1}

Cancel the common factors.

=x^2-2x+3

The quotient is x^2-2x+3.

Therefore, the correct option is D.

7 0
3 years ago
Read 2 more answers
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