$a^2-b^2 =55 \\ \\ 28^2 -27^2=55 \\ \\ 28^2 =784 \\ \\27^2 =729 \\ \\ 784-729=55 \\ \\ \\ \sf So,~the~ difference~ of~ the~ two~ squares~ of~ 28~ and~ 27~ equals~ to~ 55.$

5 0

2 years ago

Anyone want to f riend me or cha t here

vovangra [49]

Answer:

yes

Step-by-step explanation:

yes I want ☺️☺️☺️☺️☺️☺️

7 0

2 years ago

Read 2 more answers

Factor Trinomials:

notka56 [123]

Answer:

1. $2(x+2)(x+5)$

2. $8(x+4)^{2}$

Step-by-step explanation:

Problem #1:

1. Find the GCF (Greatest Common Factor)

$GCF = 2$

2. Factor out the GCF and simplify.

$2(x^{2} +7x+10)$

3. Factor $x^{2} +7x+10$

Which two numbers add up to 7 and multiply to 10?

2 and 5

Rewrite the expression using the above.

$(x+2)(x+5)$

4. Done!

$2(x+2)(x+5)$

Problem #2:

1. Find the GCF (Greatest Common Factor)

$GCF=8$

2. Factor out the GCF and simplify.

$8(x^{2} +8x+16)$

3. Use the perfect square formula. $a^{2} +2ab+b^{2} =(a+b)^{2}$

$a = x\\b=4$

$(x+4)^{2}$

4. Done!

$8(x+4)^{2}$

8 0

2 years ago