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3 years ago

HELP!!!!!!!!!! PLEASE!!!!!!!WILL MARK AS BRAINLIEST

Mathematics

2 answers:

frutty [35]3 years ago

7 0

on point S label each side of the perpendicular line 90°

Triangle RSU will always add up to 180° so 33+90= 123 180-123= 57

57 time 2 since its split into two 114° = u

114+33= 147 180 - 147=33

U=114 is your answer

Goshia [24]3 years ago

6 0

<t =33 since triangle RUT is isosceles (RU = TU)

<r + <u + <t = 180 triangle = 180

33 + <u + 33 = 180

66 + <u = 180

< u =114

<rus = < sut from the diagram

<rus + <sut = <u

x + x = 114

2x = 114

divide by 2

x = 57

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SpyIntel [72]

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3 years ago

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Genrish500 [490]

Answer: Vertical angles are congruent.

Step-by-step explanation:

In the given picture, NS and RT are intersecting line segments, intersects at point Q.

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4 years ago

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4 years ago

Rolling Dice Roll two standard dice and add the numbers. What is the probability of getting a number larger than 9 for the first

Rudik [331]

Answer:

$\frac{1}{6}$

Step-by-step explanation:

The sum is larger than 9, it means we have: 10, 11, and 12

To get the outcome is 12, we have only one way is that the two dice shows face-6. The probability to have 12 is:

P(12) = $\frac{1}{6} *\frac{1}{6}$ = $\frac{1}{36}$

To get 11, we have it two ways once dice shows face-5 and the other shows face-6 and vice versa

P(11) = 2* $\frac{1}{6} *\frac{1}{6}$ = $\frac{1}{18}$

To get 10, we have it three ways ( once dice shows face-5 and the other shows face-6 and vice versa , two dice show 5)

P(10) = 3* $\frac{1}{6} *\frac{1}{6}$ = $\frac{1}{12}$

So the probability of getting a number larger than 9 for the first time on the third roll is:

P(12) + P(11) +P(10 )

= $\frac{1}{36}$ + $\frac{1}{18}$ + $\frac{1}{12}$ = $\frac{1}{6}$

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4 years ago