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AysviL [449]
3 years ago
8

Subtraction of whole numbers is commutative. True or False

Mathematics
1 answer:
strojnjashka [21]3 years ago
3 0
It is False.

If a property is commutative in subtraction it means:  x - y    is the same as y - x.

For example    5 - 3 = 2,  but 3 - 5 = -2  so subtraction is not commutative.

But 5 + 3 = 8   ,   is the same as 3 + 5 = 8.

Addition is Commutative, but Subtraction is not commutative.

So the statement that subtraction of whole numbers is commutative is False.
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Match the given angle pair to their relationship using the figure beloe​
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Given f '(x) = (x + 1)(6 + 3x), find the x-coordinate for the relative minimum on the graph of f(x).
FinnZ [79.3K]

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x = -1

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3 0
3 years ago
the sum of three integers is 92. the second number is three times the first number. the third number is ten less than twice the
Elanso [62]

1st number = x

 2nd number = 3x

3rd number = 2x-10

x +3x + 2x-10 =92

6x - 10 = 92

6x =102

x = 102/6

x = 17

1st number = 17

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8 0
3 years ago
What is a radius of a circle given by the equation x²-2x+8y-47=0
Zolol [24]
First, we are going to rewrite it as a parabola equation.
Rewrite.
8y=-x^2+2x+47
Divide by 8.
y=-\frac{x^2}{8}+\frac{x}{4}+\frac{47}{8}
Factor out coefficient.
y=-\frac{1}{8}\left(x^2-2x\right)+\frac{47}{8}
Then, we are going to convert x into square form.
y=-\frac{1}{8}\left(x^2-2x+1\right)+\frac{1}{8}\cdot \:1+\frac{47}{8}
Convert the whole expression into square form.
y=-\frac{1}{8}\left(x-1\right)^2+\frac{1}{8}\cdot \:1+\frac{47}{8}
Simplify.
y=-\frac{1}{8}\left(x-1\right)^2+6
Subtract 6 from both sides.
y-6=-\frac{1}{8}\left(x-1\right)^2
Divide by coefficient.
-8\left(y-6\right)=\left(x-1\right)^2
Rewrite in standard form.
4\left(-2\right)\left(y-6\right)=\left(x-1\right)^2

The radius of the circle will be -2. Also, no matter what the sign says, the radius has to always be positive. 
Have a nice day! :)
7 0
3 years ago
Read 2 more answers
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