All categories

3 years ago

PLEASE SUPER URGENT!! 14 PTS PLEASE

Mathematics

1 answer:

Zepler [3.9K]3 years ago

8 0

Answer: h(x) = -1200x^2 + 1950x + 4950

=======================================

Work Shown:

f(x) = revenue from the north

f(x) = -750x^2 + 1500x + 2250

g(x) = revenue from the south

g(x) = -450x^2 + 450x + 2700

h(x) = total revenue, ie add the two revenues

h(x) = f(x) + g(x)

h(x) = (-750x^2+1500x+2250)+(-450x^2+450x+2700)

h(x) = -1200x^2 + 1950x + 4950

You might be interested in

To subtract 105 ? 73 using mental math, Sabine subtracted 105 ? 75 and got 30. What should she do next?

IRISSAK [1]

She should ask the teacher if it is correct or not

7 0

3 years ago

What is the slope of a line that contains the points (1,9) and (4,3)

Mila [183]

Answer:

The slope is -2

Step-by-step explanation:

To find the slope of a line when we have 2 points, we use the formula

m = (y2-y1)/(x2-x1)

= (3-9)/(4-1)

= -6/3

-2

4 0

4 years ago

Read 2 more answers

5(4x-7) +3 (3x+3) can someone help me please

ivann1987 [24]

Answer:

The expression 5(4x - 7) + 3(3x + 3) can be simplified to 29x - 26

Step-by-step explanation:

The first step in solving this is to apply coefficients to the contents of the brackets:

5(4x - 7) + 3(3x + 3)

= 5 × 4x - 5 × 7 + 3 × 3x + 3 × 3

= 20x - 35 + 9x + 9

Now you can group like terms:

20x - 35 + 9x + 9

= 20x + 9x - 35 + 9

= (20 + 9)x - 26

= 29x - 26

And that is the final answer.

4 0

3 years ago

SOMEONE HELP PLEASE!!!

Oliga [24]

Answer:

x = 2 1/3

y = 14 / (2 1/3) = 14 / (7/3) = 14*3/7 = 42/7 = 6

y = 6

x = 4 1/5

y = 14 / (4 1/5) = 14 / (21/5) = 14*5/21 = 70/21 = 3 7/21 = 3 1/3

y = 3 1/3

x = 7/6

y = 14 / (7/6) = 14*6 / 7 = 12

y = 12

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

When two equal forces are inclined at an angle 2a their resultant is twice as great as

swat32

Step-by-step answer:

Referring to the attached diagram, the resultant of two forces each with magnitude F and inclined to each other at 2a equals

Ra = 2Fcos(a) ..............................(1)

Similarly, the resultant of two forces each with magnitude F and inclined to each other at 2b equals

Rb = 2Fcos(b)..............................(2)

We are given that

Ra = 2Rb ....................................(3)

Substitute (1) & (2) in (3) gives

2Fcos(a) = 2(2Fcos(b))

Expand

2Fcos(a) = 4Fcos(b)

Simplify

cos(a) = 2 cos(b) QED

Note: Please note that you might have a faster response if you posted this question in the physics or the (new) Engineering section.

Have a nice day!

5 0

3 years ago