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wlad13 [49]
3 years ago
11

Please answer ASAP I really need help

Mathematics
1 answer:
I am Lyosha [343]3 years ago
4 0

Answer:

to solve, substitute each of the answer choices as the base and see which one works.

Step-by-step explanation:

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Reflect square JKLM with J(1, 4), K(6, 5), L(7, 0) and M(2, -1) in the y-axis. What are the coordinates of M'?
ANTONII [103]

Given:

Reflect square JKLM with J(1, 4), K(6, 5), L(7, 0) and M(2, -1) in the y-axis.

To find:

The coordinates of M'.

Solution:

We have, M(2, -1) .

If a  figure reflected over the y-axis then

(x,y)\to (-x,y)

Using this rule, we get

M(2,-1)\to M'(-2,-1)

Therefore, the coordinates of point M' are (-2,-1).

7 0
3 years ago
If A and B are supplementary and m A = 37°45', then m B = 142°15'.<br><br><br> True or False
BabaBlast [244]

Answer:

  True

Step-by-step explanation:

Supplementary angles total 180°.

  37°45' +142°15' = 179°60' = 180°

Angles A and B are supplementary. (true)

7 0
4 years ago
Reid gets on a Ferris Wheel from a platform 3 feet above the ground (which is the low point of the rotation). The diameter of th
Sati [7]

This corresponds to a sinusoidal graph, we have:

Radius= 20 feet, that corresponds to the amplitud (A)

One revolution takes 24 seconds, that corresponds to the period

Min= 3 feet

k=360/24=15

D= bottom distance+ amplitud=3+20=23 feet

\begin{gathered} \text{The movement is represented by the expression:} \\ y=A\cos (kx)+D \end{gathered}

Then, let x be the time, in seconds:

y=20\cos (15x)+23

a) To determine Reid's height after 1 minute= 60 seconds, substitute x=60

\begin{gathered} y=20\cos (15\cdot60)+23 \\ y=9\text{ f}eet \end{gathered}

b) To determine when Reid's height will first reach 18 feet, we have to substitute y=18 feet, and isolate x:

\begin{gathered} 18=20\cos (15x)+23 \\ 18-23=20\cos (15x) \\ -5=20\cos (15x) \\ -\frac{5}{20}=\cos (15x) \\ -\frac{1}{4}=\cos (15x) \\ By\text{ trigonometric properties:} \\ 15x=\cos ^{-1}(-\frac{1}{4})+2\pi n \\ x=\frac{\cos^{-1}(-\frac{1}{4})}{15}+\frac{2\pi n}{15} \end{gathered}

7 0
1 year ago
What is the range of the function f(x) = (x + 3)2 + 4?
Tju [1.3M]

Range of f(x)=(x + 3)^2 + 4 is [4,∞).

<u>Step-by-step explanation:</u>

Here we have , function f(x)=(x + 3)^2 + 4  , We need to find range of this function . Let's find out:

In the function f(x)=(x + 3)^2 + 4 , Let's focus on (x+3)^2 : It's a perfect square whose value will be always positive and greater then equal to zero i.e.

⇒ (x+3)^2\geq 0 , So minimum value of (x+3)^2 is 0 at x=-3 . ∴

⇒ f(x)=(x + 3)^2 + 4

⇒ f(-3)=(-3+ 3)^2 + 4

⇒ f(-3)= 4

Minimum value of f(x)=(x + 3)^2 + 4 is 4 , And maximum value of f(x)=(x + 3)^2 + 4  can be ∞ as value of x can be increased . Therefore , Range of f(x)=(x + 3)^2 + 4 is [4,∞).

7 0
4 years ago
Yesterday was the 13th. If the day after tomorrow is Wednesday, what will the date be on Saturday?
Aleks04 [339]

Saturday will be the 18th


3 0
3 years ago
Read 2 more answers
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