I need help with this one!! plsandtyy

What is the volume of this rectangular prism, given the area of the base is 14

GREYUIT [131]

Answer:

Wow, I'm learning this in class right now lol, the answer is C, 42cm cubed.

Step-by-step explanation:

The formula for finding volume fo 3d shapes is area of base x height/length.

In this problem, they give you both of those. 14 x 3 = 42, so the answer is C.

Hope this helped! If it did, please give me brainliest! It would help a lot! Thanks! :D

5 0

3 years ago

If the function rule is to divide by 10, and an output value is 7.2, what is the input value?

tatiyna

Answer:

72

Step-by-step explanation:

7.2 x 10 = 72 and 72 ÷ 10 = 7.2

4 0

4 years ago

Read 2 more answers

Melissa is saving $25 that she earned for washing her mom’s car. She earns $10 every week for doing chores, which she also saves

Fofino [41]

Answer:idk

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Sally can paint the wall in 54 minutes. If Sally and Ethan work together, they can paint the wall in 36 minutes. How much time d

MAXImum [283]

Answer:

$108\ minutes$

Step-by-step explanation:

1) we know that

Sally can paint the wall in 54 minutes

so

The 100% of the wall ------> she can paint in 54 minutes

by proportion

calculate how much is the percent of the work in 36 minutes

$\frac{100\%}{54} =\frac{x\%}{36}\\ \\x=36*100/54\\ \\x=66.67\%$

That means

Sally in 36 minutes can paint the 66.67% of the wall

2) Sally and Ethan work together, they can paint the wall in 36 minutes

so

Ethan in 36 minutes can paint (100%-66.67%)=33.33%

by proportion

Calculate how much time does it take for Ethan to paint the wall by herself

$\frac{33.33\%}{36} =\frac{100\%}{x}\\ \\x=36*100/33.33\\ \\x=108\ minutes$

6 0

3 years ago

A model for the population in a small community after t years is given by P(t)=P0e^kt.

LUCKY_DIMON [66]

$\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\\
I=\textit{initial amount}\\
r=rate\to r\%\to \frac{r}{100}\\
t=\textit{elapsed time}\\
\end{cases}$

a)

so, if the population doubled in 5 years, that means t = 5. So say, if we use an amount for "i" or P in your case, to be 1, then after 5 years it'd be 2, and thus i = 1 and A = 2, let's find "r" or "k" in your equation.

$\bf \textit{Amount of Population Growth}\\\\
A=Ie^{rt}\qquad 
\begin{cases}
A=\textit{accumulated amount}\to &2\\
I=\textit{initial amount}\to &1\\
r=rate\\
t=\textit{elapsed time}\to &5\\
\end{cases}
\\\\\\
2=1\cdot e^{5r}\implies 2=e^{5r}\implies ln(2)=ln(e^{5r})\implies ln(2)=5r
\\\\\\
\boxed{\cfrac{ln(2)}{5}=r}\qquad therefore\qquad \boxed{A=e^{\frac{ln(2)}{5}\cdot t}} \\\\\\
\textit{how long to tripling?}\quad 
\begin{cases}
A=3\\
I=1
\end{cases}\implies 3=1\cdot e^{\frac{ln(2)}{5}\cdot t}$

$\bf 3=e^{\frac{ln(2)}{5}\cdot t}\implies ln(3)=ln\left( e^{\frac{ln(2)}{5}\cdot t} \right)\implies ln(3)=\cfrac{ln(2)}{5} t
\\\\\\
\cfrac{5ln(3)}{ln(2)}=t\implies 7.9\approx t$

b)

A = 10,000, t = 3

$\bf \begin{cases}
A=10000\\
t=3
\end{cases}\implies 10000=Ie^{\frac{ln(2)}{5}\cdot 3}\implies \cfrac{10000}{e^{\frac{3ln(2)}{5}}}=I
\\\\\\
6597.53955 \approx I$

3 0

4 years ago