4 years ago

PLEASE HELP!!

Mathematics

1 answer:

SashulF [63]4 years ago

5 0

A is the right answer i think

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URGENT WILL GIVE BRAINLIEST

inna [77]

Answer:

Step-by-step explanation:

This can be written as

$log_w\frac{(x^2-6)^4}{(x^2+8)^\frac{1}{3} }$

when you divide log you should subtract the terms

$log_w(x^2-6)^4-log_w(x^2+8)^\frac{1}{3}$

Rewrite powers in the terms as below

$4log_w(x^2-6)-\frac{1}{3} log_w(x^2+8)$

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4 years ago

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4 years ago

I need help what is the correct awnser radius and diameter

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3 years ago