3 km north.
the east and west cancel out and the 5 north being greater than the two south leave you to only have to subtract the 2 south from the 5 north
Answer:
x = 27°, ∠JLK = 55°
Step-by-step explanation:
From the diagram in the question above,
The exterior angle of a triangle is equal to the sum of the two opposite side
3x+13 = 39+(2x+1)
3x+13 = 40+2x
collect like terms and solve for x
3x-2x = 40-13
x = 27°.
∠JKL = 2x+1
Substitute the value of x
∠JKL = 2(27)+1
∠JKL = 54+1
∠JKL = 55°
Answer:
-11 for the first one and 0 for the second one
Step-by-step explanation:
If a root is a+√b then another is a-√b because of quadatic formula
r2=1-√5