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Mamont248 [21]
3 years ago
8

TURILO

Mathematics
1 answer:
aivan3 [116]3 years ago
6 0

Answer – True

To begin an indirect proof, you assume the inverse of what you intend to prove is true. An indirect proof takes the conclusion from a hypothesis and assumes that the inverse is true until a contradiction is reached, thus showing that if the inverse is true there would be a contradiction. In other words, indirect proof demonstrates that something else apart from the given statement (usually algebraic or geometric) would not make sense.

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I need help understanding this. SO please help and give explanation
NikAS [45]
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5 0
3 years ago
Worth 12 Points, i spent 24
rewona [7]

Answer:

  \displaystyle m^{\frac{35}{12}}n^{-\frac{28}{15}}=\frac{m^{\frac{35}{12}}}{n^{\frac{28}{15}}}

Step-by-step explanation:

The relevant rule of exponents is ...

  (a^b·c^d)^e = a^(be)·c^(de)

Then ...

  (m^(5/4)·n^(-4/5))^(7/3) = m^(5/4·7/3)·n^(-4/5·7/3)

  = m^(35/12)·n^(-28/15)

__

Since you want positive rational exponents, you can write this as ...

  = m^(35/12)/n^(28/15)

6 0
3 years ago
What is measure of angle R?
Tema [17]
I think you need to add them all up first or do the 90 degree
8 0
3 years ago
Geometric sequences HELP ASAP!
Pani-rosa [81]

Given:

The table for a geometric sequence.

To find:

The formula for the given sequence and the 10th term of the sequence.

Solution:

In the given geometric sequence, the first term is 1120 and the common ratio is:

r=\dfrac{a_2}{a_1}

r=\dfrac{560}{1120}

r=0.5

The nth term of a geometric sequence is:

a_n=ar^{n-1}

Where a is the first term and r is the common ratio.

Putting a=1120, r=0.5, we get

a_n=1120(0.5)^{n-1}

Therefore, the required formula for the given sequence is a_n=1120(0.5)^{n-1}.

We need to find the 10th term of the given sequence. So, substituting n=10 in the above formula.

a_{10}=1120(0.5)^{10-1}

a_{10}=1120(0.5)^{9}

a_{10}=1120(0.001953125)

a_{10}=2.1875

Therefore, the 10th term of the given sequence is 2.1875.

6 0
3 years ago
Determine the unknown side lengths
Tems11 [23]

Answer:

Where is the shape?

Step-by-step explanation:

3 0
3 years ago
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