Step 1: Find the slope<span> of the </span>line<span>. To find the </span>slope<span> of the given </span>line<span> we need to get the </span>line<span> into </span>slope-intercept form<span> (</span>y<span> = mx + </span>b), which means we need to solve fory<span>: The </span>slope<span> of the </span>line<span> 3x – 5y = 9 is m = </span>3<span>/5. Therefore, the </span>slope<span> of the </span>line parallel<span> to this </span>line<span> would </span>have<span> to be m = </span>3<span>/5.
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Answer: a) 1:1
they are even. if it was 1:2 or 2:1 one of them on the graph would be taller but that are both at the same number
Find the area of one side, by using the area of a triangle formula 1/2 x height x base.
The base is given as 4 and the height is given as 6.
Area of one side = 1/2 x 4 x 6 = 12 square units.
There are 6 sides, so multiply the area of one side by 6:
12 x 6 = 72 square units.
Answer:
x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4
Step-by-step explanation:
Solve for x:
x - 1 - 2/x = 3 x + 2
Bring x - 1 - 2/x together using the common denominator x:
(x^2 - x - 2)/x = 3 x + 2
Multiply both sides by x:
x^2 - x - 2 = x (3 x + 2)
Expand out terms of the right hand side:
x^2 - x - 2 = 3 x^2 + 2 x
Subtract 3 x^2 + 2 x from both sides:
-2 x^2 - 3 x - 2 = 0
Divide both sides by -2:
x^2 + (3 x)/2 + 1 = 0
Subtract 1 from both sides:
x^2 + (3 x)/2 = -1
Add 9/16 to both sides:
x^2 + (3 x)/2 + 9/16 = -7/16
Write the left hand side as a square:
(x + 3/4)^2 = -7/16
Take the square root of both sides:
x + 3/4 = (i sqrt(7))/4 or x + 3/4 = -(i sqrt(7))/4
Subtract 3/4 from both sides:
x = (i sqrt(7))/4 - 3/4 or x + 3/4 = -(i sqrt(7))/4
Subtract 3/4 from both sides:
Answer: x = (i sqrt(7))/4 - 3/4 or x = -(i sqrt(7))/4 - 3/4
5/15 is the answer simplified is 1/3
