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likoan [24]
3 years ago
15

The function f has a domain of 1,3,5,7 and a range of 2,4,6. Could f be represented by 1,2. 3,4. 5,6. And 7,2. Justify your answ

er
Mathematics
1 answer:
Mandarinka [93]3 years ago
3 0
Yes, a function with those domain and range values could certainly be represented by those points. (1,2) and (7,2) are points with separate domain values but identical range values. This is allowed because every x value is only assigned one y value.
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2x+2y=8 in function form step by step please?
nasty-shy [4]
You could get two different functions out of this:

<u>2x + 2y = 8</u>

1). <u> 'y' as a function of 'x'</u>

Subtract  2x  from each side:  2y  = -2x + 8

Divide each side by  2 :         <em> y  =  -x + 4</em>


2). <u> 'x' as a function of 'y' :</u>

Subtract  2y  from each side:    2x  =  -2y + 8

Divide each side by  2 :        <em>  x  =  -y + 4</em>

Those two functions look the same, but that's just because the original
equation given in the problem was so symmetrical.  In general, they're
not the same function.


7 0
2 years ago
Read 2 more answers
136 is 85% of what number?
Arte-miy333 [17]
X * 0.85 = 136
           x = 136/0.85
           x = 160

hope this helps :)

3 0
3 years ago
Write the equation of a line Parallel to the given line and passes through points (-4, -3); (2, 3). Hints find the slope by usin
julia-pushkina [17]

First, we obtain the gradient (slope) of the first parallel line

\text{gradient, m}_1\text{ = }\frac{y_2-y_1}{x_2-x_1}\text{ = }\frac{3-(-3)}{2-(-4)}=\frac{6}{6}\text{ = 1}

Recall that since both lines are parallel, we have that,

m_1=m_2

Thus

m_2\text{ = 1}

Hence, we can find the equation of the parallel line given that it passes through the points (-4, -3)

Using

\begin{gathered} y\text{ = mx + c} \\ \text{where m = m}_2\text{ = 1} \\ \text{and x = -4 ,  y = -3, we have} \\ -3\text{ = 1(-4) + c} \\ -3\text{ = -4 + c} \\ 4\text{ - 3 = c} \\ c\text{ = 1} \\ \text{Thus, the equation of the line is y = (1)x + 1} \\ y\text{ = x + 1} \end{gathered}

5 0
1 year ago
Use the discriminant to determine the number and type of solutions the equation has.
lidiya [134]
Discriminant = square root (b^2 -4*a*c)
square root (64 -4*1*12) =
square root (16) =
4
Therefore it has 2 rational soltions


4 0
2 years ago
HELP PLEASE!!!!!BRAINLIEST
Greeley [361]
That is false because you have to subtract the exponents not divide
4 0
3 years ago
Read 2 more answers
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