A pair of fractions that have the same product is 1/2 and 2/4 because they are both half.
Hope I helped! Also I hoped this is what you meant by the finding a pair of fractions with same products. :D
Answer:
n= 21 option B
Step-by-step explanation:
a1= 30, d = -4, and Sn = -210
WE use sum formula
we are given with a1 and d so its arithmetic sequence
the sum formula for arithmetic sequence is
a1= 30 and d= -4 sn =-210
Plug in the values and solve for n
Now distribute the fraction n/2
-210 = 32n - 2n^2
we add 210 on both sides
-2n^2 +32n +210=0
Divide whole equation by -2
Now we factor left hand side
Product is -105 and sum is -16
-21 times (5) = -105
-21 + (5) = -16
(n-21) (n+5)=0
n -21 = 0 so n= 21
n +5 =0 so n = -5
number of terms cannot be negative so n= 21
Answer:
I believe it's D. histogram ; continuous
Step-by-step explanation:
Answer:
2013
Step-by-step explanation:
We note that 2013 has the property: since the sum of the digits of 201, 2+0+1=3, is divisible by 3, 201 is itself divisible by 3. We must now check whether any odd-numbered years before 2013 have the property. 200 is not divisible by the prime 7, so 2007 does not have this property. Likewise, the sum of the digits of 200 is 2, which is not divisible by 3, so 200 and 9=3^2 are relatively prime. Clearly 2011 does not have the desired property since every natural number is relatively prime to 1. Thus, the first odd-numbered year after 2006 that has the desired property is 2013.
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