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saveliy_v [14]
3 years ago
10

Elizabeth won a $300 gift certificate at silver gym. A membership costs $15 a month and has a one- time fee of $50. Complete the

equation that models the number of months,x, her gift certificate is will pay for a Silver gym.

Mathematics
1 answer:
tiny-mole [99]3 years ago
7 0

The correct answer is 15 x + 50 = 300

Explanation:

In an equation, the different values show a specific mathematical relationship, and the equality represented by the symbol (=) is used to find an unknown value. In the case presented, the unknown value is the number of months Elizabeth can pay using her $300 gift certificate. This means the letter x in the equation represents the number of months.

Moreover, this x should be multiplied by the month membership or $15 considering Elizabeth will need to pay this fee each month and this should be added to the one-time fee of $50. This implies the first part of the equation is 15x + 50. Finally, this value should be equal to the total money in the certificate or 300. According to this, the equation is 15x + 50 = 300.

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Andrews [41]

Answer:

6 chairs

8 desks

Step-by-step explanation:

First, we assume that all 14 items he bought were chairs, if that was to be true then the office manager would spend...

125 x 14 =  1750$

We see that he spent less then he should have so now we start to substitute desks instead of chairs, and we have to keep in mind that if we change 1 chair to a desk then the total will increase by...

515 - 125 = 390$

Now we just find the difference between the needed total and the total that we get if the office manager would by only chairs and then divide the result by 390 in order to find the number of desks, and so we get...

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And now that we know the number of desks we just subtract the number of desks from 14 and get the number of chairs, and so...

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3 years ago
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The correct option will be:  C) 0.84

<u><em>Explanation</em></u>

Formula for Correlation coefficient :

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}

First, for each point(x, y), we need to calculate x², y² and xy .

Then, we will find sum all x, y, x², y² and xy, which gives us Σx, Σy, Σx², ∑y² and Σxy

<em>(Please refer to the attached image for the table )</em>

Here we got, ∑x = 44 , ∑y = 183 , ∑x² = 362 , ∑y² = 6575 and ∑xy = 1480

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So, plugging those values into the above formula..........

r= \frac{n(\Sigma xy)-(\Sigma x)(\Sigma y)}{\sqrt{[n\Sigma x^2-(\Sigma x)^2][n\Sigma y^2-(\Sigma y)^2]}}\\ \\ r=\frac{7(1480)-(44)(183)}{\sqrt{[7(362)-(44)^2][7(6575)-(183)^2]}}\\ \\ r=\frac{10360-8052}{\sqrt{(598)(12536)}}\\ \\ r=\frac{2308}{\sqrt{7496528}}\\ \\ r=0.84

So, the value of the correlation coefficient is 0.84

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