Give the equation of the line perpendicular to the line through (3, 2) and (-2, 4) that

Plane hkp and plane rkp are two distinct planes. name the intersection of plane hkp and plane rkp.

Zielflug [23.3K]

"KP" is the name among the following choices given in the question that is the name of the intersection of plane hkp and plane rkp. The correct option among all the options that are given in the question is the first option or option "A". I hope that this is the answer that has actually come to your desired help.

3 0

3 years ago

Divide the following polynomials and then complete the quotient. Write your answer in order of decreasing powers of x.

NikAS [45]

The easiest way to do this is to put each term in the numerator over the denominator and do the division/reducing for each one. Like this: $\frac{10 x^{6} }{5 x^{2} } + \frac{20 x^{4} }{5 x^{2} } - \frac{15 x^{2} }{5 x^{2} }$ . The first term reduces to $2 x^{4}$ , the second to $4 x^{2}$ , and the third to 3. Putting them all together with the signs in between we have $2 x^{4} +4 x^{2} -3$

8 0

3 years ago

Find the surface area of the cylinder in terms of pi.

Ilia_Sergeevich [38]

Hello!

To find the surface area of a cylinder you use the equation

$SA = 2 \pi rh+2 \pi r^{2}$

SA is surface area
r is radius
h is height

Put in the values you know

$SA = 2 \pi 9 * 3 + 2 \pi 9^{2}$

Square the number

$SA = 2 \pi 9 * 3 + 2 \pi 81$

Times the 9 and 3

$SA = 2 \pi 27 + 2 \pi 81$

Multiply the 2 and 27

$SA = 54 \pi + 2 \pi 81$

Multiply the 2 and 81

$SA = 54 \pi + 162 \pi$

Add

$SA = 216 \pi$

The answer is $216 \pi$

Hope this helps!

8 0

3 years ago

Read 2 more answers

Explain why the slope b of the least-squares line always has the same sign (positive or negative) as the sample correlation coef

rodikova [14]

Answer:

b = r(sy/sx)

Step-by-step explanation:

The sign of the slope Coefficient and the correlation are the same because both the slope and correlation Coefficient evaluates the changes in one variable with respect to the other . A decrease in y as x increases will result in a negative slope value and also a negative correlation Coefficient. While increase in x which results in the increase in y imvariable will result in a positive correlation Coefficient value and r value.

Slope, b = correlation Coefficient,r (Sy /Sx)

Sx = standard deviation of x values

Sy = standard deviation of Y Values

5 0

3 years ago

Y=sqrt(x)(8x-5) find the derivative

garri49 [273]

Answer:

$\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

General Formulas and Concepts:

Algebra I

Exponentials [Fractions] - Are radicals
Exponential Rule [Rewrite]: $\displaystyle b^{-m} = \frac{1}{b^m}$

Calculus

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

f(x) = cxⁿ
f’(x) = c·nxⁿ⁻¹

Product Rule: $\displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)$

Step-by-step explanation:

Step 1: Define

$\displaystyle y = \sqrt{x}(8x - 5)$

Step 2: Differentiate

$\displaystyle f(x) = \sqrt{x}, \ g(x) = (8x - 5)$

Product Rule: $\displaystyle y' = \frac{d}{dx}[\sqrt{x}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Rewrite: $\displaystyle y' = \frac{d}{dx}[x^{\frac{1}{2}}] \cdot (8x - 5) + \sqrt{x} \cdot \frac{d}{dx}[(8x - 5)]$
Basic Power Rule: $\displaystyle y' = \frac{1}{2}x^{\frac{1}{2} - 1} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{1 - 1}$
Simplify: $\displaystyle y' = \frac{1}{2}x^{-\frac{1}{2}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8x^{0}$
Rewrite: $\displaystyle y' = \frac{1}{2x^{\frac{1}{2}}} \cdot (8x - 5) + \sqrt{x} \cdot 1 \cdot 8$
Multiply: $\displaystyle y' = \frac{8x + 5}{2x^{\frac{1}{2}}} + 8\sqrt{x}$
Rewrite: $\displaystyle y' = \frac{8x + 5}{2\sqrt{x}} + 8\sqrt{x}$
Add/Rewrite: $\displaystyle y' = \frac{24x - 5}{2\sqrt{x}}$

3 0

3 years ago