

- <u>We </u><u>have </u><u>given </u><u>two </u><u>linear </u><u>equations </u><u>that</u><u> </u><u>is </u><u>2x </u><u>-</u><u> </u><u>3y </u><u>=</u><u> </u><u>-</u><u>6</u><u> </u><u>and </u><u>x</u><u> </u><u>+</u><u> </u><u>3y </u><u>=</u><u> </u><u>1</u><u>2</u><u> </u><u>.</u>

- <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>



<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>


<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>





<u>Now</u><u>, </u><u> </u><u>Subsitute</u><u> </u><u>the </u><u>value </u><u>of </u><u>y </u><u>in </u><u>eq(</u><u> </u><u>1</u><u> </u><u>)</u><u>:</u><u>-</u>





Hence, The value of x and y is 2 and 10/3
Answer:
x-60
Step-by-step explanation:
You have to factor out the quadratic.
You know that one of the factors is x-40.
To factor:
Find a number that when added to -40, gives you -100, and also when multiplied, gives you 2400.
That such number is -60.
Add an x before it, and you get (x-60)
Answer:
character vs nature.
minor
I got it right on edge 2021
Answer: it is 15
Step-by-step explanation:
Step-by-step explanation:
Hi there!
The given equation is:
y = -2x + 5………………(i)
Comparing the equation with y = mx+c, we get;
m1 = -2
Also another equation of the line which passes through point (-4,2), we get;
(y-2) = m2(X+4)............(ii) { using the formula (y-y1) = m2(x-x2)}
According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;
m1*m2 = -1
-2*m2 = -1
or, m2 = 1/2.
Therefore, m2= 1/2.
Now, keeping the value of m2 in equation (ii).
(y-2) = 1/2(x+4)
y = (1/2)x + 4
Therefore, the required equation is: y = (1/2)x + 4.
<u>Hope</u><u> it</u><u> helps</u><u>!</u>