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Wittaler [7]
2 years ago
8

Three candidates are running for the office of Grand Satrapy of Vorania. The third- and second-place candidates received $28$ an

d $98$ votes, respectively. There were no ties. If the winner received $x\%$ of the total votes, what is the smallest possible value of $x$?
Mathematics
2 answers:
kobusy [5.1K]2 years ago
8 0
<span>So the second candidate receives $28 votes and the third candidate receives 498 votes. To be in the first place it would need just about $99 votes. Then the total number of votes would be 28 + 98 + 99 = 225. Maximum number of votes gives the smallest possible value of x, so that would be like 99 / 225 = 44%</span>
tamaranim1 [39]2 years ago
4 0

Answer:

Da answer is 44%

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\bold{\huge{\pink{\underline{ Solution }}}}

\bold{\underline{ Given }}

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\bold{\underline{ To \: Find }}

  • <u>We </u><u>have </u><u>to </u><u>find </u><u>the </u><u>value </u><u>of </u><u>x </u><u>and </u><u>y </u><u>by </u><u>elimination </u><u>method</u><u>. </u>

\bold{\underline{ Let's \: Begin }}

\sf{ 2x - 3y = -6 ...eq(1)}

\sf{ x +  3y = 12 ...eq(2)}

<u>Multiply </u><u>eq(</u><u> </u><u>2</u><u> </u><u>)</u><u> </u><u>by </u><u>2</u><u> </u><u>:</u><u>-</u>

\sf{ 2( x + 3y = 12 )}

\sf{ 2x + 6y = 24 }

<u>Subtract </u><u>eq(</u><u>1</u><u>)</u><u> </u><u>from </u><u>eq(</u><u>2</u><u>)</u><u> </u><u>:</u><u>-</u>

\sf{ 2x + 6y -( 2x - 3y) = 24 -(-6)}

\sf{ 2x + 6y - 2x + 3y = 24 + 6 }

\sf{   9y = 30 }

\sf{   y = 30/9}

\sf{\red{ y = 10/3}}

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\sf{ 2x - 3(10/3) = -6 }

\sf{ 2x - 10 = -6 }

\sf{ 2x  = -6 + 10}

\sf{ x  = 4/2}

\sf{\red{ x  = 2}}

Hence, The value of x and y is 2 and 10/3

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2 years ago
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Step-by-step explanation:

Hi there!

The given equation is:

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Also another equation of the line which passes through point (-4,2), we get;

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According to the question, they are perpendicular to eachother, So according to the condition of perpendicular lines;

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Therefore, the required equation is: y = (1/2)x + 4.

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