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3 years ago

8

Three candidates are running for the office of Grand Satrapy of Vorania. The third- and second-place candidates received $28$ an

d $98$ votes, respectively. There were no ties. If the winner received $x\%$ of the total votes, what is the smallest possible value of $x$?

2 answers:

kobusy [5.1K]3 years ago

8 0

<span>So the second candidate receives $28 votes and the third candidate receives 498 votes. To be in the first place it would need just about $99 votes. Then the total number of votes would be 28 + 98 + 99 = 225. Maximum number of votes gives the smallest possible value of x, so that would be like 99 / 225 = 44%</span>

tamaranim1 [39]3 years ago

4 0

Answer:

Da answer is 44%

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Please Need help on these

Harlamova29_29 [7]

<h2> Question # 3</h2>

Answer:

$x = 13.094$

Step-by-Step Explanation

Considering the exponential equation

$e^{x-9}-6=54$

Solving the exponentiation equation

$e^{x-9}-6=54$

$\mathrm{Add\:}6\mathrm{\:to\:both\:sides}$

$e^{x-9}-6+6=54+6$

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$\mathrm{If\:}f\left(x\right)=g\left(x\right)\mathrm{,\:then\:}\ln \left(f\left(x\right)\right)=\ln \left(g\left(x\right)\right)$

$\ln \left(e^{x-9}\right)=\ln \left(60\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(x^b\right)=b\cdot \log _a\left(x\right)$

$\ln \left(e^{x-9}\right)=\left(x-9\right)\ln \left(e\right)$

$\left(x-9\right)\ln \left(e\right)=\ln \left(60\right)$

$\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1$

$\ln \left(e\right)=1$

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Therefore, x = 13.094

<h2> Question # 4</h2>

Answer:

$x=0.386$

Step-by-Step Explanation

Considering the exponential equation

$3e^{9x}-6=91$

Solving the exponentiation equation

$3e^{9x}-6=91$

$\mathrm{Add\:}6\mathrm{\:to\:both\:sides}$

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$\mathrm{Divide\:both\:sides\:by\:}3$

$\frac{3e^{9x}}{3}=\frac{97}{3}$

$e^{9x}=\frac{97}{3}$

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$\mathrm{Apply\:log\:rule}:\quad \log _a\left(a\right)=1$

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$\mathrm{Divide\:both\:sides\:by\:}9$

$\frac{9x}{9}=\frac{\ln \left(\frac{97}{3}\right)}{9}$

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$x=0.386$

Therefore, x = 0.386

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3 years ago