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aleksandrvk [35]
3 years ago
6

F(x)=x2 what is g(x)?

Mathematics
1 answer:
Oksi-84 [34.3K]3 years ago
8 0

g(x) = (1/4)x^2 . correct option C) .

<u>Step-by-step explanation:</u>

Here we have , f(x)=x^2  and we need to find g(x) from the graph . Let's find out:

We have ,  f(x)=x^2   . From the graph we can see that g(x) is passing through point (2,1 ) . Let's substitute this point in all of the four options !

A . g(x) = (1/4x)^2

Putting (2,1) in equation g(x) = (x/4)^2 , we get :

⇒ g(2)= (\frac{2}{4} )^2

⇒ 1\neq \frac{1}{4}

Hence , wrong equation !

B . g(x) = 4x^2

Putting (2,1) in equation g(x) = 4x^2 , we get :

⇒ g(2)=4(2)^2

⇒ 1\neq 64

Hence , wrong equation !

C . g(x) = (1/4)x^2

Putting (2,1) in equation g(x) = (1/4)x^2 , we get :

⇒ g(2)= (\frac{1}{4} )2^2

⇒ 1= 1

Hence , right equation !

D . g(x) = (1/2)x^2

Putting (2,1) in equation g(x) = (1/2)x^2 , we get :

⇒ g(2)= (\frac{1}{2} )2^2

⇒ 1\neq 2

Hence , wrong equation !

Therefore , g(x) = (1/4)x^2 . correct option C) .

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On a coordinate plane, a circle has a center at (0, 0). Point (3, 0) lies on the circle.
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Answer:

The correct option is;

No, the distance from (0, 0) to (2, √6) is not 3 units

Step-by-step explanation:

The given parameters of the question are as follows;

Circle center (h, k) = (0, 0)

Point on the circle (x, y) = (3, 0)

We are required to verify whether point (2, √6) lie on the circle

We note that the radius of the circle is given by the equation of the circle as follows;

Distance \, formula = \sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}}

Distance² = (x - h)² + (y - k)² = r² which gives;

(3 - 0)² + (0 - 0)² = 3²

Hence r² = 3² and r = 3 units

We check the distance of the point (2, √6) from the center of the circle (0, 0) as follows;

\sqrt{\left (x_{2}-x_{1}  \right )^{2} + \left (y_{2}-y_{1}  \right )^{2}} = Distance

Therefore;

(2 - 0)² + (√6 - 0)² = 2² + √6² = 4 + 6 = 10 = √10²

\sqrt{\left (2-0 \right )^{2} + \left (\sqrt{6} -0 \right )^{2}} = 10

Which gives the distance of the point (2, √6) from the center of the circle (0, 0) = √10

Hence the distance from the circle center (0, 0) to (2, √6) is not √10 which s more than 3 units hence the point  (2, √6), does not lie on the circle.

4 0
3 years ago
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Answer:

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Step-by-step explanation:

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3 years ago
Two cells are viewed and measured under a microscope. The approximate diameter
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Answer:

option D. 4.7 x 10-4 m

Step-by-step explanation:

<u><em>The correct question is</em></u>

• cell P: 5.0 x 10-4 meters

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we have            

The diameter of cell P is  5*10^{-4}\ m

The diameter of cell Q is  3*10^{-5}\ m

Rewrite the diameter of cell P as    

5*10^{-4}\ m=5*10^{-4}(\frac{10}{10})=50*10^{-5}\ m

Find the difference

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Rewrite the difference as

47*10^{-5}\ m=47*10^{-5}}(\frac{10}{10})=4.7*10^{-4}\ m

7 0
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