Answer:
Step-by-step explanation:
Answer:
hope it's helpful for you
For this case we have that by definition, the equation of a line in the slope-intersection form is given by:
![y = mx + b](https://tex.z-dn.net/?f=y%20%3D%20mx%20%2B%20b)
Where:
m: It's the slope
b: It is the cut-off point with the y axis
According to the statement we have the following equation:
![y = - \frac {1} {2} x-4](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B1%7D%20%7B2%7D%20x-4)
The slope is:
![m = - \frac {1} {2}](https://tex.z-dn.net/?f=m%20%3D%20-%20%5Cfrac%20%7B1%7D%20%7B2%7D)
By definition, if two lines are parallel then their slopes are equal. Thus, a parallel line will have slope
. Therefore, the equation will be of the form:
![y = - \frac {1} {2} x + b](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B1%7D%20%7B2%7D%20x%20%2B%20b)
In the statement they tell us that
substituting we have:
![y = - \frac {1} {2} x-1](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B1%7D%20%7B2%7D%20x-1)
Answer:
The equation is:
![y = - \frac {1} {2} x-1](https://tex.z-dn.net/?f=y%20%3D%20-%20%5Cfrac%20%7B1%7D%20%7B2%7D%20x-1)