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KonstantinChe [14]
3 years ago
10

For breakfast, Clarissa can choose from oatmeal, cereal, French toast, or scrambled eggs. If she selects a breakfast at random,

what is the likelihood that she will choose oatmeal?
Mathematics
1 answer:
Sholpan [36]3 years ago
3 0
The probability that she will choose oatmeal is 1/4. Oatmeal is one choice out of the four possible choices of oatmeal, cereal, French toast, and scrambled eggs. So the answer is 1/4 or 25%.
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If 3x-y=123x−y=123, x, minus, y, equals, 12, what is the value of \dfrac{8^x}{2^y} 2 y 8 x ​ start fraction, 8, start superscrip
julia-pushkina [17]

Answer:

2^{12}=4,096

Step-by-step explanation:

You know that 3x-y=12 and have to find

\dfrac{8^x}{2^y}

Use the main properties of exponents:

1. (a^m)^n=a^{m\cdot n}

2. \dfrac{a^m}{a^n}=a^{m-n}

Note that

8=2^3,

then

7^x=(2^3)^x=2^{3\cdot x}=2^{3x}

Now

\dfrac{8^x}{2^y}=\dfrac{2^{3x}}{2^y}=2^{3x-y}

Since 3x-y=12, then 2^{3x-y}=2^{12}=4,096

3 0
3 years ago
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What is a solution for this problem 60-36/3*4
Ksivusya [100]
The answer is 12
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3 years ago
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Find the reciprocal of the following:<br><br> a. 12 b. 3 1/4 c. - 9
Eva8 [605]

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b. 3 1/4

Step-by-step explanation:

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3 years ago
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explain how you could use the greatest common factor of 8 and 20 in the distributive property to write 8 + 20 as a product​
GenaCL600 [577]

Answer: 4(5+2) or 4(2+5)

Step-by-step explanation:

8 = 2*2*2

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6 0
3 years ago
The answer to this question asap please
Mkey [24]

At 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

<h3>How to state hypothesis conclusion?</h3>

We are given;

Sample size; n = 78

population standard deviation σ = 37

Sample Mean; x' = 280

Population mean; μ = 287

The school administrator declares that mean score is more (bigger than) 280. Thus, the hypotheses is stated as;

Null hypothesis; H₀: μ > 280

Alternative hypothesis; Hₐ: μ < 280

This is a one tail test with significance level of α  = 0.13

From online tables, the critical value at α  = 0.13 is z(c) = -1.13

b) Formula for the test statistic is;

z = (x-  μ)/(σ/√n)

z = ((280 - 287) *√78 )/37

z = -1.67

c) From online p-value from z-score calculator, we have;

P[ z > 280 ] =  0.048

d) The value for z = -1.67  is smaller than the critical value mentioned in problem statement z(c) = - 1.13  , the z(s) is in the rejection zone. Therefore we reject H₀

e) We conclude that at 13% significance level, there isn't enough evidence to prove the administrators to claim that the mean score for the​ state's eighth graders on this exam is more than 280.

Read more about Hypothesis Conclusion at; brainly.com/question/15980493

#SPJ1

5 0
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