Answer:
The capability index for the process is 0.889
Step-by-step explanation:
Here, we want to compute the capability index for the process
To get this, we need some important parameters which we already have stated in the question
USL ( upper standard limit) = 0.048
LSL (lower standard limit) = 0.032
mean = 0.04
standard deviation = 0.003
We apply the formula as seen in the attachment below
Kindly understand that we are to calculate the Z upper and Z lower
The smallest value between the two will be our Z minimum
This is what we shall apply in the capability index formula which mathematically is;
Z minimum/3
From calculation:
Z lower = Z upper = 2.67
So therefore;
capability index = 2.67/3 = 0.889
Answer:
1. Which angles are adjacent.
CBX and FBC
Step-by-step explanation:
Okay so an adjacent angle is two angles with a common side. This means angles CBX and FBC are adjacent because they have the common side of "BC/CB"
Answer
2. Find the sum of the interior angles of a nonagon
1,260
Step-by-step explanation:
A nonagon is a 9 sided polygon with angles of 140. It wants the sum of all the angles. Since it has 9 sides, it has 9 angles. Now you can add 140, 9 times, or do 140 x 9. This gets you 1,260.
Answer
3. The measure of angle 3 is 101. find the measure of angle 4.
79
Step-by-step explanation.
Okay so both angles are against the same intersecting line, this means their sum must be 180. All we have to do here is subtract 180 and 101. this gets us 79.
Answer
4. Find the measure of each interior angle of a regular polygon with 12 sides.
1800
Step-by-step explanation.
Okay so a 12 sided regular polygon is a dodecagon. This has 12 angles with the degree of 150. This means 150 x 12 just like the 2nd question about nonagons. So 150 x 12 is 1800
Now that i've showed you how to do the first 4 you can apply the rest of the information on your own for 5 and the rest of the test.
20 because 16 is greater than 15 and we round the number up.
Answer:
zx=115'
Step-by-step explanation:
supplementary angles add up to 180'
180-65=115
Answer:
The time interval when
is at 
The distance is 106.109 m
Step-by-step explanation:
The velocity of the second particle Q moving along the x-axis is :

So ; the objective here is to find the time interval and the distance traveled by particle Q during the time interval.
We are also to that :
between 
The schematic free body graphical representation of the above illustration was attached in the file below and the point when
is at 4 is obtained in the parabolic curve.
So,
is at 
Taking the integral of the time interval in order to determine the distance; we have:
distance = 
= 
= By using the Scientific calculator notation;
distance = 106.109 m