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3 years ago

49-c< or equal to 45thanks

Mathematics

1 answer:

m_a_m_a [10]3 years ago

3 0

$49-c\leq45\qquad\text{subtract 49 from both sides}\\\\-c\leq-4\qquad\text{change the signs}\\\\\boxed{c\geq4}$

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What is the answere answer because I want to know if I got it right

sattari [20]

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3 years ago

The angled lines used to indicate the surfaces which are cut by the imaginary cutting-plane are called:

Scilla [17]

Answer:

Section lines

Step-by-step explanation:

Sectioning is the process of cutting a surface by an imaginary plane, the view of the surface that is cut is shown in the section view.

Section lines are used to indicate where an imaginary cutting plane cuts a material. The imaginary cut is then represented using section lines which are usually thin, crosshatched.

Section lines shows the surface that have been cut by the cutting plane. There are different ways of sectioning such as full section, half section, off set section and so on

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3 years ago

A+x+6, when a=10 and x=4

kolezko [41]

Answer:

the answer is 20. 10+4+6 is 20

Step-by-step explanation:

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3 years ago

Read 2 more answers

F(x)=-3/5x+k and if f(30)=-11 what is the value of k

Kruka [31]

Answer:

k=20.

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6 0

3 years ago

A manufacturer of banana chips would like to know whether its bag filling machine works correctly at the 421 gram setting. It is

Anastaziya [24]

Answer:

The p-value is approximately 0.0508

Step-by-step explanation:

The given parameters are;

The expected mass of banana chips bag filled by the machine, μ = 421 gams

The number of bags in the sample of bags filled by the machine, n = 26 bags

The mean mass of the bags in the sample, $\overline x$ = 413 grams

The standard deviation of the mass in the bags, s = 24 grams

The level of significance, α = 0.02

The null hypothesis, H₀; μ = 421 grams

The alternative hypothesis, Hₐ; μ < 421 grams

The test statistic is given as follows;

$t=\dfrac{\bar{x}-\mu }{\dfrac{s}{\sqrt{n}}}$

We get;

$t=\dfrac{413-421 }{\dfrac{24}{\sqrt{26}}} \approx -1.6996731712$

The t-value = -1.6996731712

The degrees of freedom df = n - 1 = 26 - 1 = 25

From an online source, we get the critical-t = 2.166587

The p-value is obtained using an online source as p(t ≤ -1.6996731712) = 0.0508

From the p-value table, we get

0.05 < p < 0.1

3 0

2 years ago