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saul85 [17]
3 years ago
6

The fraction in the beginning is throwing me off...help..!

Mathematics
1 answer:
makvit [3.9K]3 years ago
7 0

Answer:

x = -21

Step-by-step explanation:

thanks for the points gg

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Find the gradient of the line segment between the points (-1,3) and (1,-2).
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Answer:

The gradient of the line segment between the two points is -1

Step-by-step explanation:

The gradient of the line segment between two points is also known as the slope,

We  can find this by using the formula; y₂ - y₁ /  x₂ - x₁

The points given to us are;(-1,2) and (-2,3).

This implies x₁ = -1  ,     y₁=2         x₂ =  -2        y₂= 3

We can now proceed to insert our values into the formula;

Gradient = y₂ - y₁ /  x₂ - x₁

               = 3 - 2  /  -2-(-1)

                = 1  /  -2 + 1

                 =1/-1

Gradient = -1

Therefore the gradient of the line segment between the two points is -1

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3 years ago
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JulsSmile [24]

Answer:

A) y = 2x+ 6

Step-by-step explanation:

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3 years ago
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What is the measure of XYZ?<br><br> A. 186<br> B. 96<br> c. 93<br> D. 174
Natasha2012 [34]

Answer:

C 93

Step-by-step explanation:

Inscribed Angle = 1/2 Intercepted Arc

< XYZ = 1/2 (186)

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Please answer this question (10) GIVING BRAINLIEST!!
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<h3>Answer:  y = 5</h3>

==============================================================

Explanation:

For any rectangle, the diagonals are always the same length. We can use congruent triangles to prove this.

This means AC = BD.

Also, the diagonals of a rectangle cut each other in half (bisect). This indicates the following two equations

  • AP = PC
  • BP = DP

We'll use that second equation along with BP = -2x+23 and DP = 3y-6 to form the equation -2x+23 = 3y-6. This will be used later.

---------------

By the segment addition postulate, we know that

BP+DP = BD

(-2x+23)+(3y-6) = BD

BD = -2x+3y+17

Since the diagonals are equal, we also know that AC = -2x+3y+17

We are given that AC = 2x+4

Equating the two right hand sides leads to the equation 2x+4 = -2x+3y+17

---------------

The conclusion of each the last two sections was the following two equations

  • -2x+23 = 3y-6
  • 2x+4 = -2x+3y+17

We have two equations and two unknowns. We have enough info to be able to find x and y.

Let's isolate 3y in the first equation

-2x+23 = 3y-6

3y-6 = -2x+23

3y = -2x+23+6

3y = -2x+29

Then we can plug this into the second equation

2x+4 = -2x+3y+17

2x+4 = -2x+(3y)+17

2x+4 = -2x+(-2x+29)+17 .... replace 3y with -2x+29

Now solve for x

2x+4 = -2x+(-2x+29)+17

2x+4 = -2x-2x+29+17

2x+4 = -4x+46

2x+4x = 46-4

6x = 42

x = 42/6

x = 7

We then use this to find y

3y = -2x+29

3y = -2(7)+29

3y = -14+29

3y = 15

y = 15/3

y = 5

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3 years ago
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We know that domain of log(x) is &forall; x>0.
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