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forsale [732]
3 years ago
13

Which answer represents the domain of the logarithmic function given below? f(x)=log7x

Mathematics
2 answers:
Georgia [21]3 years ago
5 0
We know that domain of log(x) is ∀ x>0.
=>
domain of log(7x) is also ∀ x>0, or (0,∞) in interval notation.
Ira Lisetskai [31]3 years ago
5 0
The answer is x>0. I have apex to.
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Suppose that triangle TUV is an isosceles with the base VU.
vekshin1
Set them equal to each other and solve
3x + 39 = 4x +34
-x=-5
X=5
Plug it in
3(5) + 39 = 54
4(5) +34 = 54
For the final angle ,
54 + 54 = 108
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Fuji apples cost $3.00 per pound, and Golden Delicious apples cost $2.00 per pound. A childcare center purchases 30 pounds of a
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Of all customers purchasing automatic garage-door openers, 70% purchase a chain-driven model. Let X = the number among the next
otez555 [7]

Answer:

P(X > 10), n = 15, p = 0.7

P(X > 10) =P(10 < X ≤ 15) = P(11 ≤ X ≤ 15) = P(X = 11, 12, 13, 14, 15)

=P(X = 11) + P(X =12) + P(X = 13) + P(X =14) + P(X = 15) (because these are disjoint events)

Step-by-step explanation:

See attached image for detailed explanation

7 0
3 years ago
Six sophomores and 14 freshmen are competing for two alternate positions on the debate team. Which expression represents the pro
Elanso [62]

Answer:

<em>Choose the first alternative</em>

\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}

Step-by-step explanation:

<u>Probabilities</u>

The requested probability can be computed as the ratio between the number of ways to choose two sophomores in alternate positions (N_s) and the total number of possible choices (N_t), i.e.

\displaystyle P=\frac{N_s}{N_t}

There are 6 sophomores and 14 freshmen to choose from each separate set. There are 20 students in total

We'll assume the positions of the selections are NOT significative, i.e. student A/student B is the same as student B/student A.

To choose 2 sophomores out of the 6 available, the first position has 6 elements to choose from, the second has now only 5

_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C} \text{ ways to do it}

The total number of possible choices is

_{2}^{20}\textrm{C} \text{ ways to do it}

The probability is then

\boxed{\displaystyle P=\frac{_{1}^{6}\textrm{C}\ _{1}^{5}\textrm{C}}{_{2}^{20}\textrm{C}}}

Choose the first alternative

7 0
3 years ago
Read 2 more answers
Does the set of numbers form a Pythagorean triple? Explain.
Natali [406]

Answer:

NO

Step-by-step explanation:

Either 3, 5 and 6 satisfy the Pythagorean Theorem or they do not.  Here we start with a^2 + b^2 = c^2 and substitute 6 for c (because 6 is the largest of the set):  Is 3^2 + 5^2 = 6^2?  9 + 25 = 36?  NO

7 0
2 years ago
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