Answer:
41.27m/s
Explanation:
According to law of conservation of momentum
m1u1+m2u2 = (m1+m2)v
m1 and m2 are the masses
u1 and u2 are the initial velocities
v is the velocity after impact
Given
m1 = 0.2kg
u1 = 43.7m/s
m2 = 45.9g = 0.0459kg
u2 = 30.7m/s
Required
Velocity after impact v
Substitute the given parameters into the formula
0.2(43.7)+0.0459(30.7) = (0.2+0.0459)v
8.74+1.409 = 0.2459v
10.149 = 0.2459v
v = 10.149/0.2459
v = 41.27m/s
Hence the speed of the golf ball immediately after impact is 41.27m/s
Hello!
1. Answer: D.
2. Answer: A.
3. Answer: C.
4. Answer: I believe the correct answer is A.
5. Answer: D.
6. Answer: B.
7: Answer: C.
I really hope this helped! :)
Answer:
A
. It will allow vertically polarized light to pass through it.
Explanation:
Polarization is the attribute in which waves oscillate in a particular direction relative to the direction of travel. The direction of polarization determines the type of polarized light produced. Since the chemical molecules are vertically aligned, it will only allow vertically polarized light pass through it.