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amid [387]
3 years ago
11

Armando is the CEO for a successful large business. He wants to create a visual aid to represent the relationships between diffe

rent levels of authority in the company. What does Armando want to create?
a hierarchy
an organizational chart
a mission
a key performance indicator
Physics
2 answers:
xeze [42]3 years ago
7 0
<h3><em>your answer will be an organizational chart </em></h3><h3><em>hope this helps have a nice day :)</em></h3>
Butoxors [25]3 years ago
3 0
The Answer Is: An Organizational Chart.
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Two asteroids are 75000 m apart one has a mass of 8 x 10^7 kg if the force of gravity between them is 1.14 what is the mass of t
vaieri [72.5K]
I’m going to say B

I hope this helped
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3 years ago
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If a planet has a radius 20% greater than that of the Earth but has the same mass as the Earth, what is the acceleration due to
Vaselesa [24]

Answer:

g_2=6.8125 m^2/sec

Explanation:

We know that

Acceleration due to gravity g is given by the formula

g= \frac{GM}{r^2}

G= gravitational constant

M= mass of the Earth

r= radius of the earth

g_1 = GM/r_1^2

Let acc. due to gravity after radius is 20% greater be g_2

then

g_2=GM/r_2^2

=> g1/g2 = (r_2/r_1)^2 => g2 = 9.81/1.2^2 = 6.8125

5 0
3 years ago
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A policeman is chasing a criminal across a rooftop at 10 m/s. He decides to jump to the next building which is 2 meters across f
Alexus [3.1K]
At 10 m/s, it will take
  (2 m)/(10 m/s) = 0.2 s
to bridge the gap.

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3 0
3 years ago
An electron is released from rest at a distance of 0.470 m from a large insulating sheet of charge that has uniform surface char
ArbitrLikvidat [17]

Answer:

Part a)

W = 1.58 \times 10^{-20} J

Part b)

v = 1.86 \times 10^5 m/s

Explanation:

Part a)

Electric field due to large sheet is given as

E = \frac{\sigma}{2\epsilon_0}

\sigma = 4.00 \times 10^{-12} C/m^2

now the electric field is given as

E = \frac{4.00 \times 10^{-12}}{2(8.85 \times 10^{-12})}

E = 0.225 N/C

Now acceleration of an electron due to this electric field is given as

a = \frac{eE}{m}

a = \frac{(1.6 \times 10^{-19})(0.225)}{9.1 \times 10^{-31}}

a = 3.97 \times 10^{10}

Now work done on the electron due to this electric field

W = F.d

d = 0.470 - 0.03

d = 0.44 m

So work done is given as

W = (ma)(0.44)

W = (9.11 \times 10^{-31})(3.97 \times 10^{10})(0.44)

W = 1.58 \times 10^{-20} J

Part b)

Now we know that work done by all forces = change in kinetic energy of the electron

so we will have

W = \frac{1}{2}mv^2 - 0

1.58 \times 10^{-20} = \frac{1}{2}(9.1\times 10^{-31})v^2

v = 1.86 \times 10^5 m/s

7 0
3 years ago
ANSWER ASAP
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B the desert was once covered in water

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